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Andrew [12]
3 years ago
8

Plz help me with these question ( just making sure So I don’t get them wrong! :)

Mathematics
1 answer:
chubhunter [2.5K]3 years ago
8 0
1. x intercept is (10,0)
y intercept is (0,6)

2. x intercept is (4,0)
y intercept is (0, -1)

3. x intercept is ( 4,0)
y intercept is (0,8)

hope this helps :) !
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Quarters are currently minted with weights normally distributed and having a standard deviation of 0.065. New equipment is being
Ilya [14]

Answer:

Yes, the new equipment appear to be effective in reducing the variation of​ weights.

Step-by-step explanation:

We are given that Quarters are currently minted with weights normally distributed and having a standard deviation of 0.065.

A simple random sample of 25 quarters is obtained from those manufactured with the new​ equipment, and this sample has a standard deviation of 0.047.

Let \sigma = <u><em>standard deviation of weights of new equipment.</em></u>

SO, Null Hypothesis, H_0 : \sigma \geq 0.065      {means that the new equipment have weights with a standard deviation more than or equal to 0.065}

Alternate Hypothesis, H_A : \sigma < 0.065      {means that the new equipment have weights with a standard deviation less than 0.065}

The test statistics that would be used here <u>One-sample chi-square</u> test statistics;

                           T.S. =  \frac{(n-1)s^{2} }{\sigma^{2} }  ~ \chi^{2}__n_-_1

where, s = sample standard deviation = 0.047

           n = sample of quarters = 25

So, <u><em>the test statistics</em></u>  =  \frac{(25-1)\times 0.047^{2} }{0.065^{2} }  ~  \chi^{2}__2_4   

                                     =  12.55

The value of chi-square test statistics is 12.55.

Now, at 0.05 significance level the chi-square table gives critical value of 13.85 at 24 degree of freedom for left-tailed test.

Since our test statistic is less than the critical value of chi-square as 12.55 < 13.85, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which <u><em>we reject our null hypothesis</em></u>.

Therefore, we conclude that the new equipment have weights with a standard deviation less than 0.065.

5 0
3 years ago
Which conversion factors are used to convert 12 m/s to kilometers per minute?
Lera25 [3.4K]

Answer:

see the procedure

Step-by-step explanation:

we have

12\ \frac{m}{s}

Remember that

1\ km=1,000\ m

To convert m to km multiply by (1/1,000)

1\ min=60\ sec

To convert sec to min multiply by (1/60)

substitute

12\ (\frac{(1/1,000)}{(1/60)})=12(\frac{60}{1,000})=0.72\ \frac{km}{min}

7 0
3 years ago
At noon the temperature on Jessica's porch was 75 f .Then the temperature dropped d degrees. By midnight, the temperature on the
Nina [5.8K]

Answer:

D is 12

Step-by-step explanation:

75 - 63 = 12 = D

6 0
2 years ago
The graphs of two linear equations ax + by = c and bx - ay = c, where a, b, c are all not equal to zero.
marin [14]
Let us find the slopes of the two lines

ax+by=c, slope m1 = -a/b

bx-ay=c, slope m2 = b/a

m1*m2 = (-a/b)(b/a) = -1

Therefore the two lines are perpendicular so the answer is D
4 0
3 years ago
2) Complete the table.<br>x<br>20<br>200<br>2000<br>15<br>20​
Dimas [21]
I think it’s 25 but I’m not too sure
3 0
3 years ago
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