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2 years ago

In circle B with the measure of minor arc AC= 84°, find m

Mathematics

1 answer:

ELEN [110]2 years ago

3 0

Answer:

m<ADC = 42°

Step-by-step explanation:

Based on the inscribed angle theorem, the inscribed angle, m<ADC is ½ the measure of minor arc AC.

If minor arc is given as 84°, therefore:

m<ADC = ½(84)

m<ADC = 42°

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Yesterday Annie walked 9/10 mile to her friends house.together to he library which is the best estimate for how far Annie walked

Novay_Z [31]

1. 9/10 + 9/10 =18/10 = 1 8/10 = 1 4/5

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2 years ago

A sample value that lies very far away from the majority of the other sample values is _____.

Elan Coil [88]

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3 years ago

Solve for h. -18+7h>12+9h

Evgen [1.6K]

Answer:

$h$

Step-by-step explanation:

$-18+7h>12+9h$

Add 18 to both sides:

$-18+7h+18>12+9h+18$

$7h>9h+30$

Subtract 9h from both sides:

$7h>9h+30$

$-2h>30$

Multiply both sides by -1 and flip the symbol:

$\left(-2h\right)\left(-1\right)$

$2h$

Divide both sides by 2:

$\frac{2h}{2}$

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4 0

3 years ago

What is the slope-intercept form of the equation y - 7= -5/2(x+4)

GREYUIT [131]

The first thing I would probably do is distribute (multiply) the -5/2 into the parenthesis:

= (-5/2)x + (-20/2)

Notice how I am not putting the x into the fraction. This is to make it easier to see the slope-intercept form.

Lets simplify the (-20/2) and then add 7 to both sides:

y - 7 = (-5/2)x - 10

y = (-5/2)x - 3

Your answer would then be:

y = (-5/2)x - 3

y = mx + b

Since it is now in the requested format.

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2 years ago

These ordered pairs, {(2,4) (3,6) (4,8) (5,10)}, are a function. True False

ki77a [65]

Answer:

True

Step-by-step explanation:

In order for a relation (a set of ordered pairs) to be considered a function, every value in the domain (the set of all the first numbers in the pair) is associated with one value in the range (the set of all second numbers in the pair). This is easiest to see visually. Our domain is the set {2, 3, 4, 5} and our range is the set {4, 6, 8, 10}, and we can visualize the ordered pair (2, 4) as an "arrow" starting a 2 in the domain and ending at 4 in the range. When seen this way, a relation is a function if every value in the domain only has one arrow coming out of it. We can see from the attached picture that the ordered pairs in the problem are a function, so this statement is true.

8 0

3 years ago