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kirza4 [7]
3 years ago
11

Can someone help me with this ?? Im totally lost on this one ...

Mathematics
2 answers:
Shtirlitz [24]3 years ago
7 0

So first of all b is a variable and this variable has a value of 5 so replace b with 5 and imagine there is a multiplication sign between the 3 and 5 (since they are not spaced out meaning you multiply) assuming you are using order of operations on this problem you would first find 5 (b) squared (muliplyed by the power of two) and multiply that answer (the answer of 5 squared) by 3 and then take the product of the answer you just got and subtract that from 5 (b)   Assuming you are not using order of operations you would first multiply 3 by 5 (b) and it would equal 15 then take 15 and multiply it by the power of 2 and then subract b      Hope this helps you understand

castortr0y [4]3 years ago
4 0
When b = 5,
3b
3 {b }^{2}  - b = 3( {5}^{2} ) - 5 \\  = 75 - 5 = 70
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2 7/9 is A. real number

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The following two-way table describes student's
guajiro [1.7K]

P ( work/ senior ) = 0.14

The attached table

required

P ( work/ senior )

This is calculated using:

P ( work/ senior ) = n ( work/ senior )/ n ( senior ).

n ( work/ senior ) = 5

n ( senior ) = 25 + 5 + = 35

So:

P ( work/ senior ) = 5/35

P ( work/ senior ) = 0.14

Add 25+5+5 (because that is all the numbers in the 'Seniors' row) and then take the 5 that is in the 'Work' column and put that over 25. (5/25 fraction as a percent is 14).

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1 year ago
Solve and show how you did 5 (x-1) + 3 = 13
Goryan [66]
5(x-1) + 3 = 13
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4 0
3 years ago
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A number is greater than 8 The same number of possible solutions to the inequality
Gre4nikov [31]

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Step-by-step explanation:

5 0
2 years ago
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Write each fraction as the sum of a whole number and a fraction less than 1
Tpy6a [65]

Given:

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To find:

The each fraction as the sum of a whole number and a fraction less than 1.

Solution:

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\dfrac{6}{5}=\dfrac{5+1}{5}

\dfrac{6}{5}=\dfrac{5}{5}+\dfrac{1}{5}

\dfrac{6}{5}=1+\dfrac{1}{5}

Therefore, the given fraction \dfrac{6}{5} can be written as 1+\dfrac{1}{5}.

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\dfrac{11}{7}=\dfrac{7+4}{7}

\dfrac{11}{7}=\dfrac{7}{7}+\dfrac{4}{7}

\dfrac{11}{7}=1+\dfrac{4}{7}

Therefore, the given fraction \dfrac{11}{7} can be written as 1+\dfrac{4}{7}.

The given fraction is \dfrac{21}{4}.

\dfrac{21}{4}=\dfrac{20+1}{4}

\dfrac{21}{4}=\dfrac{20}{4}+\dfrac{1}{4}

\dfrac{21}{4}=5+\dfrac{1}{4}

Therefore, the given fraction \dfrac{21}{4} can be written as 5+\dfrac{1}{4}.

7 0
3 years ago
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