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solniwko [45]
3 years ago
7

To compute a19 mod N, the modular exponential algorithms that we studied would do 8 modular multiplications (5 squarings and 3 m

ultiplications by a). What is the minimum number of modular multiplications needed to compute a19 mod N if you are free to use any sequence of modular multiplications.)
Mathematics
1 answer:
IRINA_888 [86]3 years ago
8 0

Answer:

Answer for the question:

To compute a19 mod N, the modular exponential algorithms that we studied would do 8 modular multiplications (5 squarings and 3 multiplications by a). What is the minimum number of modular multiplications needed to compute a19 mod N if you are free to use any sequence of modular multiplications.)

is given in the attachment.

Step-by-step explanation:

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Let's set it up like this:
0.513=\frac{\left(2x\right)^2}{\left(0.05-x\right)}
Multiply both sides by 0.05-x
0.513\left(0.05-x\right)=\frac{\left(2x\right)^2}{0.05-x}\left(0.05-x\right)
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We are then going to use the distributive property. Since we also know that the opposite of an number that is squared is the square root, we can also apply that. We would be left with something like this:
x=-\frac{0.513+\sqrt{0.673569}}{8},\:x=\frac{\sqrt{0.673569}-0.513}{8}
The variable x can be both positive or negative.
We have found successfully our answer.

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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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