Area of a right angled triangle whose sides containing the right angle are 12 dm and 5 dm is _

Mathematics

1 answer:

valkas [14]3 years ago

4 0

Answer:

60 cm

Step-by-step explanation: how I got your answer is by multiplying 5 times 12

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If bethany earned $51,740 last year, how much did she earn per week?

Ronch [10]

52.14 dollars per week.

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4 years ago

Simplify square root of 144x^12y^20

k0ka [10]

$~~~\sqrt{144 x^{12} y^{20}}\\\\=\left(144 x^{12} y^{20} \right)^{\tfrac 12}~~~~~~~~~~~~~~~~~~~~~~~;\left[\sqrt a = a^{\tfrac 12 } \right]\\\\=\left(144 \right)^{\tfrac 12} \cdot \left(x^{12 \right)^{\tfrac 12} \cdot \left(y^{20} \right)^{\tfrac 12}\\\\=\left(12^2 \right)^{\tfrac 12} \cdot x^{\tfrac{12}2} \cdot y^{\tfrac{20}2}\\\\=12 x^6y^{10}$

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2 years ago

Read 2 more answers

6. help me out please ill mark you brainlist

Colt1911 [192]

Answer:

w = 5

Step-by-step explanation:

Combining like terms is a very important part to this equation!

5.2w - 1.4 = 3.2w + 8.6

I added 1.4 to the right side first, though you must do it to the left side of the equation as well

5.2w - 1.4 + (1.4) = 3.2w + 8.6 + (1.4)

5.2w = 3.2w + 10

Combine the remaining like terms. I subtracted 3.2w from both sides.

5.2w + (-3.2w) = 3.2w + (-3.2) +10

2w = 10

Now divide

2w = 10

w = $\frac{10}2}$

w = 5

3 0

3 years ago

Two chemical plants are releasing waste into a holding tank. Plant 1 releases waste twice as fast as plant 2. Together they fill

tatiyna

Answer:

6 hours.

Step-by-step explanation:

Let t represent time taken by plant 1 in hours to release the waste.

Part of waste released by plant 1 in one hour would be $\frac{1}{t}$ .

We have been given that two chemical plant 1 releases waste twice as fast as plant 2, so time taken by plant 2 to release the waste would be $2t$ .

Part of waste released by plant 2 in one hour would be $\frac{1}{2t}$ .

We are also told that together they fill the tank in 4 hours. So part of tank filled by both plants working together in one hour would be $\frac{1}{4}$ .