Greatest to least 3.008 3.825 3.09 3.18

F(x) = a(X + 3)2 + 16 a = ?

joja [24]

Answer:

14 bro 14uhhhjhjjjjkkk

6 0

3 years ago

What is 0.08 as a percent.

kakasveta [241]

8 percent

Mark brainliest please

Hope this helps you

4 0

3 years ago

Read 2 more answers

Construct an equation that has n = 6 as its solution. Use n on both sides of the equation.

nevsk [136]

Answer:

See Explanation

Step-by-step explanation:

Required

Determine any equation where n = 6

$n = 6$

Add n to both sides

$n + n = 6 + n$

$2n = 6 + n$ ----- This is 1 equation

$n = 6$

Multiply both sides by n

$n * n = 6 * n$

$n^2 = 6n$ ----- This is another

$n = 6$

Add 5n to both sides

$n + 5n = 6 + 5n$

$6n = 6 + 5n$ ---- This is another

Subtract 10 from both sides

$6n - 10 = 6 - 10 + 5n$

$6n - 10 = -4 + 5n$

$6n - 10 = 5n - 4$ --- This is another

You can have as many equations as possible

4 0

3 years ago

35. For the following exercises, given each set of information, find a linear equation satisfying the conditions, if possible.

Montano1993 [528]

Answer:

The linear equation for the line which passes through the points given as (-2,8) and $(4,6), is written in the point-slope form as $y=-\frac{1}{3} x-\frac{26}{3}$ .

Step-by-step explanation:

A condition is given that a line passes through the points whose coordinates are (-2,8) and (4,6).

It is asked to find the linear equation which satisfies the given condition.

Step 1 of 3

Determine the slope of the line.

The points through which the line passes are given as (-2,8) and (4,6). Next, the formula for the slope is given as,

$m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

Substitute $6 \& 8$ for $y_{2}$ and $y_{1}$ respectively, and 4&-2 for $x_{2}$ and $x_{1}$ respectively in the above formula. Then simplify to get the slope as follows, $m=\frac{6-8}{4-(-2)}$

$\begin{aligned}&m=\frac{-2}{6} \\&m=-\frac{1}{3}\end{aligned}$

Step 2 of 3

Write the linear equation in point-slope form.

A linear equation in point slope form is given as,

$y-y_{1}=m\left(x-x_{1}\right)$

Substitute $-\frac{1}{3}$ for m,-2 for $x_{1}$ , and 8 for $y_{1}$ in the above equation and simplify using the distributive property as follows, $y-8=-\frac{1}{3}(x-(-2))$\\ $y-8=-\frac{1}{3}(x+2)$\\ $y-8=-\frac{1}{3} x-\frac{2}{3}$$