I think the answer is D. hours because its variation does not depend on another variable
Answer:
5b-5
Step-by-step explanation:
When doing these kinds of problems you want to do dributive property which means you multiply whatever number is outside of the (), which is 5, and multiply that by b and 1.
when numbers are outside the () and right next to them without anything like +,-, or a division sign, it means to multiply.
Answer:
-1,2
Step-by-step explanation:
4-5=-1
3-1=2
y2-y1
x2-x1
Answer:
The answer is "9 and 7".
Step-by-step explanation:
Given:
![A=\left[\begin{array}{cc}7&9\\0&9\end{array}\right]](https://tex.z-dn.net/?f=A%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D7%269%5C%5C0%269%5Cend%7Barray%7D%5Cright%5D)
Using formula:
![\to |\left[\begin{array}{cc}7&9\\0&9\end{array}\right]-\lambda \left[\begin{array}{cc}1&0\\0&1\end{array}\right] |=0\\\\\\ \to |\left[\begin{array}{cc}7&9\\0&9\end{array}\right]- \left[\begin{array}{cc}\lambda&0\\0&\lambda\end{array}\right] |=0\\\\\\\to|\left[\begin{array}{cc}7-\lambda &9\\0&9-\lambda\end{array}\right]|=0\\\\\\\to|(7-\lambda)(9-\lambda)|=0\\\\\to (7-\lambda)(9-\lambda)=0\\\\\to 7-\lambda=0 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 9-\lambda=0\\\\](https://tex.z-dn.net/?f=%5Cto%20%7C%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D7%269%5C%5C0%269%5Cend%7Barray%7D%5Cright%5D-%5Clambda%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D1%260%5C%5C0%261%5Cend%7Barray%7D%5Cright%5D%20%7C%3D0%5C%5C%5C%5C%5C%5C%20%5Cto%20%7C%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D7%269%5C%5C0%269%5Cend%7Barray%7D%5Cright%5D-%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D%5Clambda%260%5C%5C0%26%5Clambda%5Cend%7Barray%7D%5Cright%5D%20%7C%3D0%5C%5C%5C%5C%5C%5C%5Cto%7C%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D7-%5Clambda%20%269%5C%5C0%269-%5Clambda%5Cend%7Barray%7D%5Cright%5D%7C%3D0%5C%5C%5C%5C%5C%5C%5Cto%7C%287-%5Clambda%29%289-%5Clambda%29%7C%3D0%5C%5C%5C%5C%5Cto%20%287-%5Clambda%29%289-%5Clambda%29%3D0%5C%5C%5C%5C%5Cto%207-%5Clambda%3D0%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%209-%5Clambda%3D0%5C%5C%5C%5C)
1. Find the surface area of the rectangular prism. (1 point)
<span>Measures are 2, 3, and 4 inches. Let W=2, L=3, H=4 </span>
<span>a rectangular has six sides, the total surface area is equal to 6 plains: </span>
<span>2*W*L + 2*L*H + 2*L*W </span>
<span>= 2*(W*L + L*H + L*W) </span>
<span>= 2 * (2*3 + 3*4 + 4*2) </span>
<span>= 2 * ( 6 + 12 + 8 ) </span>
<span>= 2 * 26 </span>
<span>= 52 ................... the last choice </span>
<span>2. A cube has a side length of x feet. Which expression represents the surface area of the cube? (1 point) </span>
<span>Area of one face = x^2, Total Area of 6 faces = 6*x^2 = 2x^2 units </span>
<span>3. Find the surface area of the cylinder. Use 3.14 for pi . (1 point) </span>
<span>Length: 15 cm, Diameter: 2 cm </span>
<span>A cylinder has 3 surfaces: two circles + one curved surface area </span>
<span>...... two circles of 2cm diameter (1cm radius) </span>
<span>A = pi*r^2 = 3.14*1*1 = 3.14 sq. cm ...... two circles' area = 6.28 sq.cm </span>
<span>Curved surface area = circumference * length </span>
<span>.... circumference = pi*d = 3.14 * 2 = 6.28 cm ......... length = 15 </span>
<span>curved surface area = 6.28*15 = 94.2 sq. cm </span>
<span>Add both for total surface area = 6.28 + 94.2 = 100.48 sq.cm </span>
<span>4. The bottom of a shopping bag measures 8 inches by 10 inches. The bag has a height of 12 inches. How much paper is needed to make the bag? (1 point) </span>
<span>two pieces of paper ... one for bottom = 8*10 = 80 sq.in </span>
<span>the other ... height * perimeter of the bottom = 12*(2*(10+8)) = 12 * 2 * 18 = 432 sq.in </span>
<span>Add both: 80 + 432 = 512 sq.in <<<<<<<<<<<</span>
