The mass of radioactive material remaining after 50 years would be 48.79 kilograms
<h3>How to determine the amount</h3>
It is important to note that half - life is the time it takes for the amount of a substance to reduce by half its original size.
Given the radioactive decay formula as
m(t)=120e−0.018t
Where
t= 50 years
m(t) is the remaining amount
Substitute the value of t


Find the exponential value
m(t) = 48.788399
m(t) = 48.79 kilograms to 2 decimal places
Thus, the mass of radioactive material remaining after 50 years would be 48.79 kilograms
Learn more about half-life here:
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The answer is 16in.
Let the radius and height of cylinder A be Ra and Hb respectively and the radius and height of cylinder B be Rb and Hb respectively.
Using similar shapes:
Ra/Ha= Rb/Hb
5.6/Ha=1.4/4
Ha=(4×5.6)/1.4
Ha=22.4/1.4
Ha=16in
Answer:30 centimeters in 1 minute
Answer:
length of a single chain link = 5.33 cm
Step-by-step explanation:
Given data: chain contained 1000 chain links
total length was 0.0533km
<em>1km = 1000m </em>
<em> 1m = 100cm therefore 1km = 100000cm</em>
<em />
total length in cm = 0.0533* 100000
total length in cm = 5330 cm
length of a single chain link = 5330/1000
length of a single chain link = 5.33 cm
Subtract magazine from total:
25 -5 = 20
Divide by number of erasers:
20/4 = 5
Each eraser cost $5