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1 year ago

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A car starts on a trip and travels at an average speed of 50 miles per hour. Two hours later, a second car starts on the same tr

ip and travels at an average speed of 70 miles per hour.
(a) Find the distance each vehicle has traveled when the second car has been on the road for t hours.
first car
second car

(b) Use the result of part (a) to write the distance between the first car and the second car as a function of t.
d =

(c) Write the ratio of the distance the second car has traveled to the distance the first car has traveled as a function of t.

1 answer:

umka21 [38]1 year ago

7 0

The distance traveled by first car is 50t + 100.

The distance traveled by second car is 70t.

The distance between the two cars after time, t is d = 100 - 20t.

The ratio of the distance traveled by the cars is (70t) / (50t + 100).

<h3>Distance traveled by each vehicle is calculated as follows;</h3>

The distance traveled by each vehicle at the given time is calculated as follows;

<h3>Distance traveled by first car</h3>

D₁ = speed x time

D₁ = 50(t + 2)

D₁ = 50t + 100

<h3>Distance traveled by the second car</h3>

D₂ = 70t

<h3>Distance between the two cars after time, t</h3>

d = D₁ - D₂

d = (50t + 100) - 70t

d = 100 - 20t

<h3>Ratio of the distance traveled by the cars</h3>

D₂/D₁ = (70t) / (50t + 100)

Learn more about distance traveled by a vehicle here: brainly.com/question/6504879

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a

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b

Method B this is because the faulty breaks are less

Step-by-step explanation:

The number of microchips broken in method A is $n_1 = 400$

The number of faulty breaks of method A is $X_1 = 32$

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The difference between proportions of improperly broken microchips for the two breaking methods is mathematically represented as

$K = [p_1 - p_2 ] \pm z_{0.95} * SE$

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$K = [0.08 - 0.07 ] \pm 1.96 *0.0186$

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