Let s = the speed of the slower train in km/hrs+10 = the speed of the faster train in km/hrLet t = time in hrs for the slower train to go 160 kmt-5 = time in hrs for faster train to go 160 km---------------Slower train:(1)
160=s.t
Faster train:(2) 160=(s+10) .(t-.5)From (1)(1) t=160/s
use the relations given in following screenshot and then use quadratic equation.
The first 5 terms of the arithmetic sequence with first term -10 and common difference -12 are ...
-10, -22, -34, -46, -58
A BUSSINESS MEETING A GROUP MEETING AS WHILE!!!!!!!!!!!!!!!!!!!
Answer:
<h2>34.88feet</h2>
Step-by-step explanation:
The set up forms a right angle triangle with the length of the ladder being the hypotenuse and the angle of elevation is 29.32°. USing SOH, CAH TOA to determine the distance of the building from the base of the ladder.
The distance we are looking fir will be the adjacent. According to CAH.
cos29.32°= x/40
x = 40cos29.32°
x = 34.88feet (to the nearest hundredth)
The ladder is 34.88feet away from the building
Answer:
Average Velocity= 70 miles per hour
Step-by-step explanation:
Distance= s
Time = t
s(t)=10t^2
Putting the values
s(2) = 10 (2)^2= 10&4
s= 40
s(5) = 10 (5)^2 = 10*25
S(5)= 250
The average velocity is defined as the rate of change of speed in unit time.
So
Speed= distance/time
Velocity = Speed in a definite direction
Average Velocity= Displacement/ Time
Average Velocity= Change in distance/ Change in time
s(5) - s(2)/ t(5)- t(2)
= 250-40/5-2= 210/3= 70 miles per hour