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hichkok12 [17]
3 years ago
8

A car is at a distance s, in miles from its starting point in t hours, given by s(t)=10t^2. Find s(2) and s(5). Find s(5)-s(2).

What does this represent? Find the average rate of change from t=2 to t=5. This is the average velocity
Mathematics
1 answer:
weeeeeb [17]3 years ago
4 0

Answer:

Average Velocity= 70 miles per hour

Step-by-step explanation:

Distance= s

Time = t

s(t)=10t^2

Putting the values

s(2) = 10 (2)^2= 10&4

s= 40

s(5) = 10 (5)^2 = 10*25

S(5)= 250

The average velocity is defined as the rate of change of speed in unit time.

So

Speed= distance/time

Velocity = Speed in a definite direction

Average Velocity= Displacement/ Time

Average Velocity= Change in distance/ Change in time

s(5) - s(2)/ t(5)- t(2)

= 250-40/5-2= 210/3= 70 miles per hour

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Step-by-step explanation:

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thirty six and nine thousandths = 36.009

36.009 < 40

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Simplify the following Questions. (IMPORTANT NOTE!!! #'s 2 AND 7 MUST BE IN SCIENTIFIC NOTATION!!!!!) 1.) (x)²(2xy³)^5 2.) (4x10
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Answer:

Step-by-step explanation:

Hint :

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2) (4x10^{8})^{2}=4^{2}*x^{2}*(10^{8})^{2}\\\\=16*x^{2}*10^{8*2}\\\\=1.6*10*x^{2}*10^{16}\\\\=1.6x^{2}*10^{16+1}\\\\=1.6x^{2}10^{17}

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5 0
3 years ago
Shreya and beth each improved their yards by planting rose bushes and ornamental grass. They brought their supplies from the sam
frutty [35]

Answer:

  • <u><em>The cost of one rose bush is $ 9 and the cost on one bunch pf ornamental grass is $ 8.</em></u>

Explanation:

Name the variables and build a system of two equations with two unknowns.

<u>1. Variable r</u>: cost of one rose bush

<u>2. Variable g</u>: cost of one bunch of ornamental grass.

<u>3. First equation</u>:

  • Shreya spent $68 on 4 rose bushes and 4 bunches of ornamental grass.

        4r + 4g = 68

<u>4. Second equation</u>:

  • Beth spent $115 on 11 rose bushes and 2 bunches of ornaments grass.

  • 11r + 2g = 115

<u>5. System of equations</u>:

  • 4r + 4 g = 68     equation 1
  • 11r + 2g = 115     equation 2

<u>6. Solve the system</u>

a) Divide the equation 1 by 2:

  • 2r + 2g  =  34     equation 1a
  • 11r + 2g = 115     equation 2

b) Subtract equation 1a from equation 2:

  • 11r - 2r = 115 - 34
  • 9r = 81
  • r = 81 / 9
  • r = 9

c) Substitute the value of r into the equation 1a:

  • 2(9) + 2g = 34
  • 9 + g = 17
  • g = 17 - 9
  • g = 8

<u>7. Conclusion</u>:

The cost of one rose bush is $ 9 and the cost on one bunch pf ornamental grass is $ 8.

7 0
3 years ago
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