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likoan [24]
3 years ago
12

Complete the paragraph proof. Given: ∠ABR and ∠ACR are right angles AB ≅ BC BC ≅ AC Prove: bisects ∠BAC

Mathematics
2 answers:
dolphi86 [110]3 years ago
8 0

The answer is <BAR ≅<CAR :)

koban [17]3 years ago
3 0

Answer:

∠BAR=∠CAR [∴ΔABR≅ΔACR]

Step-by-step explanation:

In ΔABR and ΔACR

AB=AC=X [ ∴AB≅BC, and BC≅AC, So AB≅AC]

∠ABR = ∠ACR [ each being 90°]

AR is common.

ΔABR ≅ ΔACR [ RHS]

RHS means if in two right triangles hypotenuse and one side of a triangle is equal to hypotenuse and other side then the two triangles are congruent.

So ,∠BAC is bisected.

i.e, ∠BAR=∠CAR [ CPCT ]

Hence proved.

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3 years ago
The length of a rectangle is 12 in. and the perimeter is 56 in. find the width of the rectangle
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The perimeter p of the rectangle with length l and width w is:
p = 2l + 2w
that is, two times its length and two times its width, lets solve for the width w and substitute known data:
<span>p = 2l + 2w
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w = (56 - 24)/2
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w = 16
therefore the width of the rectangle is 16 in
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