The answer is <BAR ≅<CAR :)
Answer:
∠BAR=∠CAR [∴ΔABR≅ΔACR]
Step-by-step explanation:
In ΔABR and ΔACR
AB=AC=X [ ∴AB≅BC, and BC≅AC, So AB≅AC]
∠ABR = ∠ACR [ each being 90°]
AR is common.
ΔABR ≅ ΔACR [ RHS]
RHS means if in two right triangles hypotenuse and one side of a triangle is equal to hypotenuse and other side then the two triangles are congruent.
So ,∠BAC is bisected.
i.e, ∠BAR=∠CAR [ CPCT ]
Hence proved.
Hope this helps :).
13 hamburgers and 9 hot dogs
Supplementary angles are two angles with a sum of 18 0 ∘ 180 ^\circ 180∘ . A common case is when they lie on the same side of a straight line.
Answer - KJM and KJH
If i'm wrong please tell me
y = mx + b
y = 2x + 24
m = 2