Question

Complete the paragraph proof. Given: ∠ABR and ∠ACR are right angles AB ≅ BC BC ≅ AC Prove: bisects ∠BAC

Answer 1

The answer is <BAR ≅<CAR :)

Answer 2

Answer:

∠BAR=∠CAR [∴ΔABR≅ΔACR]

Step-by-step explanation:

In ΔABR and ΔACR

AB=AC=X [ ∴AB≅BC, and BC≅AC, So AB≅AC]

∠ABR = ∠ACR [ each being 90°]

AR is common.

ΔABR ≅ ΔACR [ RHS]

RHS means if in two right triangles hypotenuse and one side of a triangle is equal to hypotenuse and other side then the two triangles are congruent.

So ,∠BAC is bisected.

i.e, ∠BAR=∠CAR [ CPCT ]

Hence proved.