Complete the paragraph proof. Given: ∠ABR and ∠ACR are right angles AB ≅ BC BC ≅ AC Prove: bisects ∠BAC
2 answers:
The answer is <BAR ≅<CAR :)
Answer:
∠BAR=∠CAR [∴ΔABR≅ΔACR]
Step-by-step explanation:
In ΔABR and ΔACR
AB=AC=X [ ∴AB≅BC, and BC≅AC, So AB≅AC]
∠ABR = ∠ACR [ each being 90°]
AR is common.
ΔABR ≅ ΔACR [ RHS]
RHS means if in two right triangles hypotenuse and one side of a triangle is equal to hypotenuse and other side then the two triangles are congruent.
So ,∠BAC is bisected.
i.e, ∠BAR=∠CAR [ CPCT ]
Hence proved.
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