Question

Which of the following populations is most likely to be in Hardy-Weinberg equilibrium with respect to a gene, Floppy? Floppy has two alleles “F” and “f”. Assume f(F) = p and f(f) = q. A. A population in which females whose fathers had FF or Ff prefer to mate with males with FF or Ff, while females whose fathers had ff, prefer to mate with males with ff. B. A population for which p+q = 1 and p2 + 2pq + q2 = 1. C. A population for which p=0.5, q = 0.5, and the frequency of the heterozygote is 0.5. D. A population founded by a few individuals, blown to Hawaii from mainland North America 20 generations ago. E. A population for which p=0.5, and the frequency of the FF homozygote is 0.5.

Answer 1

Answer:

Option B, A population for which p+q = 1 and p2 + 2pq + q2 = 1

Explanation:

As per Hardy Weinberg's first equation,  the sum of probability of occurrence of two allele at the locus is equal to one.

Floppy has two genes i.e F and f and  f(F) = p and f(f) = q then

$p+q=1$

As per Hardy Weinberg's second equation

$p^{2} + q^2+2pq = 1$

which shows that

Frequency of occurence of genotype FF is a given population is $p^2$

Frequency of occurence of genotype ff is a given population is $q^2$

Frequency of occurence of genotype FF is a given population is $2pq$