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Elden [556K]
3 years ago
11

-5x + 12 - 7x = -3(5x + 8)

Mathematics
1 answer:
nikitadnepr [17]3 years ago
7 0

Simplify -5x + 12 - 7x to -12x + 12

-12x + 12 = -3(5x + 8)

Expand

-12x + 12 = -15x - 24

Add 15x to both sides

-12x + 12 + 15x = -24

Simplify 12x + 12 + 15x to 3x + 12

3x + 12 = -24

Subtract 12 from both sides

3x = -24 - 12

Simplify -24 - 12 to -36

3x = -36

Divide both sides by 3

x = -36/3

Simplify 36/3 to 12

<u>x = -12</u>

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What other information do you need in order to prove the triangles congruent using the SAS congruence postulate
iren [92.7K]

AC is perpendicular to BD.

<h3>Further explanation</h3>
  • We observe that both the ABC triangle and the ADC triangle have the same AC side length. Therefore we know that \boxed{ \ \overline{AC} \cong \overline{AC} \ } is reflexive.
  • The length of the base of the triangle is the same, i.e., \boxed{ \ \overline{BC} = \overline{CD} \ }.
  • In order to prove the triangles congruent using the SAS congruence postulate, we need the other information, namely \boxed{ \ AC \bot BD \ }. Thus we get ∠ACB = ∠ACD = 90°.

Conclusions for the SAS Congruent Postulate from this problem:

  • \boxed{ \ \overline{BC} = \overline{CD} \ }
  • ∠ACB = ∠ACD
  • \boxed{ \ \overline{AC} = \overline{AC} \ }

- - - - - - - - - -

The following is not other or additional information along with the reasons.

  • ∠CBA = ∠CDA no, because that is AAS with ∠ACB = ∠ACD and \boxed{ \ \overline{AC} \cong \overline{AC} \ }
  • ∠BAC = ∠DAC no, because that is ASA with \boxed{ \ \overline{AC} \cong \overline{AC} \ } and ∠ACB = ∠ACD.
  • \boxed{ \ \overline{BC} = \overline{CD} \ } no, because already marked.

- - - - - - - - - -

Notes

  • The SAS (Side-Angle-Side) postulate for the congruent triangles: two sides and the included angle of one triangle are congruent to two sides and the included angle of another triangle; the included angle properly represents the angle formed by two sides.
  • The ASA (Angle-Side-Angle) postulate for the congruent triangles: two angles and the included side of one triangle are congruent to two angles and the included side of another triangle; the included side properly represents the side between the vertices of the two angles.  
  • The SSS (Side-Side-Side) postulate for the congruent triangles: all three sides in one triangle are congruent to the corresponding sides within the other.
  • The AAS (Angle-Angle-Side) postulate for the congruent triangles: two pairs of corresponding angles and a pair of opposite sides are equal in both triangles.  
<h3>Learn more</h3>
  1. Which shows two triangles that are congruent by ASA?  brainly.com/question/8876876  
  2. Which shows two triangles that are congruent by AAS brainly.com/question/3767125
  3. About vertical and supplementary angles brainly.com/question/13096411  
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The CEO of a large electric utility claims that more than 75 percent of his customers are very satisfied with the service they r
vichka [17]

Answer:

z=\frac{0.77-0.75}{\sqrt{\frac{0.75(1-0.75)}{100}}}=0.462  

Now we can find the p value using the alternative hypothesis with this probability:

p_v =P(z>0.462)=0.322  

Since the p value is large enough, we have evidence to conclude that the true proportion for this case is NOT significanctly higher than 0.75 since we FAIL to reject the null hypothesis at any significance level lower than 30%

Step-by-step explanation:

Information provided

n=100 represent the random sample selected

\hat p=0.77 estimated proportion of students that are satisfied

is the value that we want to test

z would represent the statistic

p_v represent the p value

System of hypothesis

We want to verify if more than 75 percent of his customers are very satisfied with the service they receive, then the system of hypothesis is.:  

Null hypothesis:p\leq 0.75  

Alternative hypothesis:p > 0.75  

The statistic is given by:

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

Replacing the info given we got:

z=\frac{0.77-0.75}{\sqrt{\frac{0.75(1-0.75)}{100}}}=0.462  

Now we can find the p value using the alternative hypothesis with this probability:

p_v =P(z>0.462)=0.322  

Since the p value is large enough we have evidence to conclude that the true proportion for this case is NOT significanctly higher than 0.75 since we FAIL to reject the null hypothesis at any significance level lower than 30%

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