|-4a+10|=2<br> solving absolute value eqations

Please! #12, Thank you so much!

vovikov84 [41]

A. 168 feet
b. 1 yard = 3 feet
168*3=504 so, 168 feet =504 yards
c. 504 yards*$15=7560
d. $7560

4 0

2 years ago

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The ratio of boys to girls on a swimming team is 4 to 3. The team has 35 members how many are girls

diamong [38]

Answer:

See below:

Step-by-step explanation:

Hello! I hope you are having a nice day. My name is Galaxy and I will be helping you today!

We can solve this problem in two steps, one being Comprehension and another being Solving. I'll start off with Comprehension.

Comprehension

We can see that based of the problem, for every batch of 7 kids, there are 4 boys and 3 girls. That means that we can split the total, which is 35, into groups of 7 and seeing how many girls and boys there are.

Now that we know what we need to figure out and what to do, we can begin solving.

Solving

So, for every group of 7 kids there are 4 boys and 3 girls. We can divide 35 by 7 to find how many of these identical groups there are.

$35 \div 7=5$

We know that there are 5 such groups of 4 boys and 3 girls each. Therefore, we can multiply 4 and 3 by 5 as there are 5 such groups to find our total.

$4*5=20\\$

We know there are 20 boys.

$3*5=15$

We know there are 15 girls.

We can check this by seeing if this adds up,

$15+20=35?\\35=35$

Therefore, our answer is there are 15 girls and 20 boys.

5 0

2 years ago

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98 POINTS EASY

irina [24]

Answer:

11x+4+5=180 ok first we have to put all the naked numbers on one side and the x's number on one side, and by doing that a easier way to do that is you switch the spots but their symbols - and + change so if its negative - its going to turn into a + positive and + to a -

11x = 180 - 5 - 4

11x = 171 and since theres mutliplication 11 times x which is 11x, were going to divide

x = 171/11 and the out come is with decimals (15.54545...etc)

x=11 is incorrect

~batmans wife dun dun dun....

3 0

3 years ago

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g Suppose the population 10-year cumulative incidence of prostate cancer among 70-year old men is 0.06. Further, suppose 260 men

Rainbow [258]

Answer:

There is not enough statistical evidence to conclude that the cumulative incidence of prostrate cancer among 50-year old men differs from that of 70-year old men

Step-by-step explanation:

The population 10 year cumulative incidence of prostrate cancer among 70 year old men, p = 0.06

The number of 50 year old men in the sample, n = 260 men

The number of the sampled men that developed prostrate cancer = 13 men

The significance level, α = 0.05

Let the null hypothesis, H₀: $\hat{p}$ = p

The alternative hypothesis, Hₐ: $\hat{p}$ ≠ p

The standard score, $z_{\alpha /2}$ = 1.96

The test statistic, 'z', is given as follows;

$z=\dfrac{\hat{p}-p}{\sqrt{\dfrac{p \cdot q}{n}}}$

$\hat{p}$ = 13/260 = 0.05

q = 1 - p = 1 - 0.06 = 0.94

$Therefore, \ z=\dfrac{0.05-0.06}{\sqrt{\dfrac{0.06 \times 0.94}{260}}} = \dfrac{\sqrt{9165} }{141} \approx -0.68$

From the z-table, we find the p-value as follows;

P(z ≈ -0.68) = 0.24825

Therefore, given that the p-value, 0.24825 is larger than the significance level, α/2 = 0.025, we fail to reject the null hypothesis, and therefore, there is not enough statistical evidence to conclude that the cumulative incidence of prostrate cancer among 50-year old men differs from that of 70-year old men

5 0

2 years ago

REAL ANSWERS ONLY

marin [14]

Answer:

271

Step-by-step explanation:

6 0

2 years ago

|-4a+10|=2 solving absolute value eqations