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2 years ago

13

Tiana helped make signs for the school marching band’s fundraiser. Each side of the square sign she made was 60 3/4 centimeters.

What is the perimeter of the sign? Write your answer in simplest form

1 answer:

Minchanka [31]2 years ago

3 0

Answer:

243

Step-by-step explanation:

60 3/4 × 4 (sides)

60×4 = 240

3/4×4 = 12/4 = 3

240+3 = 243

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Explain how to write 50,000 using exponents

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The answer would be 5x10^4

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2 years ago

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The ratio of girls to boys in Mr. Smith's homeroom is 3:4. The ratio in Mr. Smith's homeroom to students in the whole 7th grade

Leno4ka [110]

3:4 = G:B

1:5 = Mr. Smith's class: 7th Grade

2:7= 7th: Middle school

12 girls = 3 units

1 unit = 12/3= 4

Boys = 4x4= 16

<em>Whole class = 28 students</em>

Class : Grade = 1:5 <em> 7 = number of units in Mr. Smith's class</em>

28 = 1 unit

5 units= 28x5= 140 <em>There are 140 kids in the grade</em>

140 = 2 units

1 unit = 140/2= 70

70x7=490

<u><em>There are 490 students in the whole grade</em></u>

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2 years ago

The ratio of children to adults at family movie night is 5 to 4. A total of 72 people showed up at this weeks movie night. How m

N76 [4]

The answer is 40 I think

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3 years ago

The number of chocolate chips in a bag of chocolate chip cookies is approximately normally distributed with mean of 1262 and a s

Andrew [12]

Answer:

a) 1186

b) Between 1031 and 1493.

c) 160

Step-by-step explanation:

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Normally distributed with mean of 1262 and a standard deviation of 118.

This means that $\mu = 1262, \sigma = 118$

a) Determine the 26th percentile for the number of chocolate chips in a bag. 

This is X when Z has a p-value of 0.26, so X when Z = -0.643.

$Z = \frac{X - \mu}{\sigma}$

$-0.643 = \frac{X - 1262}{118}$

$X - 1262 = -0.643*118$

$X = 1186$

(b) Determine the number of chocolate chips in a bag that make up the middle 95% of bags.

Between the 50 - (95/2) = 2.5th percentile and the 50 + (95/2) = 97.5th percentile.

2.5th percentile:

X when Z has a p-value of 0.025, so X when Z = -1.96.

$Z = \frac{X - \mu}{\sigma}$

$-1.96 = \frac{X - 1262}{118}$

$X - 1262 = -1.96*118$

$X = 1031$

97.5th percentile:

X when Z has a p-value of 0.975, so X when Z = 1.96.

$Z = \frac{X - \mu}{\sigma}$

$1.96 = \frac{X - 1262}{118}$

$X - 1262 = 1.96*118$

$X = 1493$

Between 1031 and 1493.

(c) What is the interquartile range of the number of chocolate chips in a bag of chocolate chip cookies?

Difference between the 75th percentile and the 25th percentile.

25th percentile:

X when Z has a p-value of 0.25, so X when Z = -0.675.

$Z = \frac{X - \mu}{\sigma}$

$-0.675 = \frac{X - 1262}{118}$

$X - 1262 = -0.675*118$

$X = 1182$

75th percentile:

X when Z has a p-value of 0.75, so X when Z = 0.675.

$Z = \frac{X - \mu}{\sigma}$

$0.675 = \frac{X - 1262}{118}$

$X - 1262 = 0.675*118$

$X = 1342$

IQR:

1342 - 1182 = 160

7 0

3 years ago

The perimeter of a playing field for a certain sport is 242 ft. the field is a rectangle, and the length is 47 ft longer than t

Mariulka [41]

242-94 = 148 (length is 47 more than the width, you double the length to get the perimeter, so you double 47 which equals 94)
148/4 = 37 (4 being the 4 sides of the rectangle)

width = 37
length = 84

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3 years ago