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lord [1]
3 years ago
13

Tiana helped make signs for the school marching band’s fundraiser. Each side of the square sign she made was 60 3/4 centimeters.

What is the perimeter of the sign? Write your answer in simplest form
Mathematics
1 answer:
Minchanka [31]3 years ago
3 0

Answer:

243

Step-by-step explanation:

60 3/4 × 4 (sides)

60×4 = 240

3/4×4 = 12/4 = 3

240+3 = 243

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Write an equation for the sentence "The product of a number n and 7.7 equals 112.42." Solve for the variable.
pishuonlain [190]

Answer:

7.7n=112.42

n=14.6

Step-by-step explanation:

The product is the result obtained by multiplying two factors. Then, the sentence ""The product of a number n and 7.7 equals 112.42" can be expressed with the following equation:

7.7n=112.42

To solve for the variable "n", you has two apply the Division property of equality and divide both sides of the equation by 7.7

Therefore, the value of "n" is:

\frac{7.7n}{7.7}=\frac{112.42}{7.7}\\\\n=14.6

8 0
3 years ago
The y-intercept of the line whose equation is 7x - 4y = 8 is what
Anni [7]
The y intercept is when x is 0. So, we have to plug in 0 for x. You can do this in many different ways as well.
7(0)-4y=8
-4y=8
Divide both sides by -4.
Y=-2
So, the Y intercept is -2 (0,-2).
6 0
3 years ago
Solve ? <br><br>-4-4(-x-1)=-4(6+2x)​
soldier1979 [14.2K]

-4-4(-x-1)=-4(6+2x)\\\\-4+4x+4=-24-8x\\\\4x=-24-8x \ \ /+8x\\\\12x=-24 \ \ /:12\\\\\huge\boxed{x=-2}

7 0
3 years ago
On the day a coffee shop first opened, it had 140 customers. 65% of the customers ordered a large coffee.
ziro4ka [17]
140 (number of customers) * .65 (% of customers who ordered a large coffee) = 91 customers who ordered a large coffee
4 0
3 years ago
Read 2 more answers
The length of time that an auditor spends reviewing an invoice is approximately normally distributed with a mean of 600 seconds
Bumek [7]
Answer: 11.5% 

Explanation:


Since 1 minute = 60 seconds, we multiply 12 minutes by 60 so that 12 minutes = 720 seconds. Thus, we're looking for a probability that the auditor will spend more than 720 seconds. 

Now, we get the z-score for 720 seconds by the following formula:

\text{z-score} =  \frac{x - \mu}{\sigma}

where 

t = \text{time for the auditor to finish his work } = 720 \text{ seconds}&#10;\\ \mu = \text{average time for the auditor to finish his work } = 600 \text{ seconds}&#10;\\ \sigma = \text{standard deviation } = 100 \text{ seconds}

So, the z-score of 720 seconds is given by:

\text{z-score} = \frac{x - \mu}{\sigma}&#10;\\&#10;\\ \text{z-score} = \frac{720 - 600}{100}&#10;\\&#10;\\ \boxed{\text{z-score} = 1.2}

Let

t = time for the auditor to finish his work
z = z-score of time t

Since the time is normally distributed, the probability for t > 720 is the same as the probability for z > 1.2. In terms of equation:

P(t \ \textgreater \  720) &#10;\\ = P(z \ \textgreater \  1.2)&#10;\\ = 1 - P(z \leq 1.2)&#10;\\ = 1 - 0.885&#10;\\  \boxed{P(t \ \textgreater \  720)  = 0.115}

Hence, there is 11.5% chance that the auditor will spend more than 12 minutes in an invoice. 
8 0
3 years ago
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