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PilotLPTM [1.2K]
3 years ago
5

PLEASE HELP!!!!

Mathematics
1 answer:
allochka39001 [22]3 years ago
5 0

Answer:

  no solution (the solution set is the empty set: { })

Step-by-step explanation:

Dividing by -3 give you ...

  |x +2| < -4

An absolute value cannot be negative, so this has no solution.

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Montano1993 [528]

Answer:

to make it perpendicular the slope as to be -5 (opposite reciprocal of the original)

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3 years ago
Three cubes of each side 4cm are joining end to end. Find the surfacing area of resulting cuboid.
nignag [31]
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3 years ago
Multiply
Dmitriy789 [7]

Answer:

The product of given two fractions is

\frac{4(x+2)}{(x-1)(x+3)}

Therefore \frac{2(2+3)}{x(x-1)}\times \frac{4x(x+2)}{10(x+3)}=\frac{4(x+2)}{(x-1)(x+3)}

Step-by-step explanation:

Given expression is  

\frac{2(2+3)}{x(x-1)}\times \frac{4x(x+2)}{10(x+3)}

To find the product of two given fractions as below :

\frac{2(2+3)}{x(x-1)}\times \frac{4x(x+2)}{10(x+3)}=\frac{2(5)}{x(x-1)}\times \frac{2x(x+2)}{5(x+3)}

=\frac{10}{x(x-1)}\times \frac{2x(x+2)}{5(x+3)}

=\frac{20x(x+2)}{5x(x-1)(x+3)}

=\frac{20x^2+40x}{(5x^2-5x)(x+3)} (multiply each term in the factor to each term in the another factor )

=\frac{20x^2+40x}{5x^3+15x^2-5x^2-15x}  ( adding the like terms )

=\frac{20x^2+40x}{5x^3+10x^2-15x}

=\frac{5x(4x+8)}{5x(x^2+2x-3)}

=\frac{4(x+2)}{(x-1)(x+3)}

Therefore \frac{2(2+3)}{x(x-1)}\times \frac{4x(x+2)}{10(x+3)}=\frac{4(x+2)}{(x-1)(x+3)}

Therefore the product of given two fractions is \frac{4(x+2)}{(x-1)(x+3)}

6 0
3 years ago
Justin drew a scale drawing of a community college. The
melisa1 [442]

Answer:

36 centimeters

Step-by-step explanation:

always start with the bigger number first then divide 72 ÷ 2 = 36 then divide 72 ÷ 36 = 2 then the actual building will be 36

5 0
3 years ago
NEED HELP ASAP (RADICALS)
worty [1.4K]
It is obvious that the radicals with negative sign tends to be less than those that are positive. So from there you already know a basic order. Now to be sure, you can use a calculator or just solve by squaring the whole number to find the radical form.
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