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Aleksandr [31]
3 years ago
9

(1,-2) is the answer I just need the work, worked out.

Mathematics
1 answer:
harina [27]3 years ago
5 0
the answer is (1,-2)
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The circumference of a circle is 28.888 centimeters. What is the circle's radius?
DanielleElmas [232]

Answer:

4.6

Step-by-step explanation:

28.888 / 3.14 = 9.2

9.2 / 2 = 4.6

5 0
2 years ago
Find the product (b-2at^2)(3b-3at^2)
Maurinko [17]

Answer: 3b^2-9bat^2+6a^2t^4

Step-by-step explanation:

To solve this problem you must apply the proccedure shown below:

- Apply the Distributive property.

- Remember that, according the exponents properties, when you multiply two powers with equal base, you must add the exponents.

- Add the like terms.

Therefore, you obtain that the product is the following:

(b-2at^2)(3b-3at^2)=3b^2-3bat^2-6bat^2+6a^2t^4=3b^2-9bat^2+6a^2t^4

8 0
3 years ago
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Caleb took 24 photos as the zoo. One eighth of his photos are of giraffes. How many of Caleb's photos are of giraffes?
jeyben [28]
The answer you are looking for is: 
(1/8)*24=
3 
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7 0
3 years ago
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Astronomers measure large distances in light-years. One light-year is the distance that light can travel in one year, or approxi
maksim [4K]

13.6 = 10, 3, 0.6

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6 0
2 years ago
You are given the following information obtained from a random sample of 5 observations. 20 18 17 22 18 At 90% confidence, you w
Margaret [11]

Answer:

a

  The null hypothesis is  

         H_o  : \mu  =  21

The Alternative  hypothesis is  

           H_a  :  \mu<   21

b

     \sigma_{\= x} =   0.8944

c

   t = -2.236

d

  Yes the  mean population is  significantly less than 21.

Step-by-step explanation:

From the question we are given

           a set of  data  

                               20  18  17  22  18

       The confidence level is 90%

       The  sample  size  is  n =  5  

Generally the mean of the sample  is  mathematically evaluated as

        \= x  =  \frac{20 + 18 +  17 +  22 +  18}{5}

       \= x  =  19

The standard deviation is evaluated as

        \sigma =  \sqrt{ \frac{\sum (x_i - \= x)^2}{n} }

         \sigma =  \sqrt{ \frac{ ( 20- 19 )^2 + ( 18- 19 )^2 +( 17- 19 )^2 +( 22- 19 )^2 +( 18- 19 )^2 }{5} }

         \sigma = 2

Now the confidence level is given as  90 %  hence the level of significance can be evaluated as

         \alpha = 100 - 90

        \alpha = 10%

         \alpha =0.10

Now the null hypothesis is  

         H_o  : \mu  =  21

the Alternative  hypothesis is  

           H_a  :  \mu<   21

The  standard error of mean is mathematically evaluated as

         \sigma_{\= x} =   \frac{\sigma}{ \sqrt{n} }

substituting values

         \sigma_{\= x} =   \frac{2}{ \sqrt{5 } }

        \sigma_{\= x} =   0.8944

The test statistic is  evaluated as  

              t =  \frac{\= x - \mu }{ \frac{\sigma }{\sqrt{n} } }

substituting values

              t =  \frac{ 19  - 21 }{ 0.8944 }

              t = -2.236

The  critical value of the level of significance is  obtained from the critical value table for z values as  

                   z_{0.10} =  1.28

Looking at the obtained value we see that z_{0.10} is greater than the test statistics value so the null hypothesis is rejected

6 0
3 years ago
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