All categories

3 years ago

Help due in 45 minutes!!

Mathematics

1 answer:

Nat2105 [25]3 years ago

3 0

Answer:

(14,-1)

Step-by-step explanation:

okay so first you need to use the "x=4y+10" in the first equation.

Rewrite as

3(4y+10) +11y=7

Distribute the 3(4y+10)

Rewrite as

12y+30

You'll have the equation

12y +30 +11y= 7

Subtract the 7 from both sides

12y+30+11y-7= 0

Combine like terms

23y+23=0

the best thing to do here is divide the equation by 23.

23/23 = 1

you'll have

y + 1 = 0

this simplifies to

y= -1

use this y value to solve for x

the easiest way to do this is start with the equation

x = 4y +10

Substitute the y for -1

x = -4(-1) +10

x = 4 +10

x = 14

the solution point is

(14,-1)

You might be interested in

What is the slope of a line perpendicular to the line whose equation is x - y = 6. Fully reduce your answer. Answer: Submit Answ

NikAS [45]

Answer:

Explanation:

The standard form of an equation is expressed as y = mx+b

m is the slope

Given the equation x - y = 6

Rewrite in standard form;

-y = -x + 6

Multiply through by -1

-(-y) = -(-x) - 6

y = x - 6

Compare with the standard equation

mx = 1x

mx+b

m is the slope

Given

5 0

1 year ago

The sum of the interior angles of a polygon is 1620 how many sides does the polygon have

Olenka [21]

Answer:

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Whats the sum of the polynomials (2x3 − 5x − 1) + (4x3 + 8x + 3)

Ipatiy [6.2K]

Answer: 23x

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

If y = 8 cm, what is the area of the blue section of this shape?

Ivahew [28]

Answer:

56 cm squared

Step-by-step explanation:

First things first: Cop one triangle off the rectangle, and attach it to the other one, so the shape looks like a L

Now I can actually solve this:

The left side is 8 cm (because y = 8 cm)

The top is 10 cm

The middle is 6 cm

The inside left is 3 cm

And the very bottom is 2 cm

First, we'll solve for the newly constructed rectangle: 3 x 2. That equals 6.

Next, solve for the longer rectangle: 10 x 5. That's 50.

Now, add the two areas, and we get 56. So the area of the whole thing is 56 cm squared.

(Please keep in mind that I could be wrong, so double check it for me, thanks!)

7 0

2 years ago

i f N(-7,-1) is a point on the terminal side of ∅ in standard form, find the exact values of the trigonometric functions of ∅.

Natali [406]

Answer:

$sin\ \varnothing = \frac{-1}{10}\sqrt 2$

$cos\ \varnothing = \frac{-7}{10}\sqrt 2$

$tan\ \varnothing = \frac{1}{7}$

$cot\ \varnothing = 7$

$sec\ \varnothing = \frac{-5}{7}\sqrt 2$

$csc\ \varnothing = -5\sqrt 2$

Step-by-step explanation:

Given

$N = (-7,-1)$ --- terminal side of $\varnothing$

Required

Determine the values of trigonometric functions of $\varnothing$ .

For $\varnothing$ , the trigonometry ratios are:

$sin\ \varnothing = \frac{y}{r}$ $cos\ \varnothing = \frac{x}{r}$ $tan\ \varnothing = \frac{y}{x}$

$cot\ \varnothing = \frac{x}{y}$ $sec\ \varnothing = \frac{r}{x}$ $csc\ \varnothing = \frac{r}{y}$

Where:

$r^2 = x^2 + y^2$

$r = \sqrt{x^2 + y^2$

In $N = (-7,-1)$

$x = -7$ and $y = -1$

So:

$r = \sqrt{(-7)^2 + (-1)^2$

$r = \sqrt{50$

$r = \sqrt{25 * 2$

$r = \sqrt{25} * \sqrt 2$

$r = 5 * \sqrt 2$

$r = 5 \sqrt 2$

<u>Solving the trigonometry functions</u>

$sin\ \varnothing = \frac{y}{r}$

$sin\ \varnothing = \frac{-1}{5\sqrt 2}$

Rationalize:

$sin\ \varnothing = \frac{-1}{5\sqrt 2} * \frac{\sqrt 2}{\sqrt 2}$

$sin\ \varnothing = \frac{-\sqrt 2}{5*2}$

$sin\ \varnothing = \frac{-\sqrt 2}{10}$

$sin\ \varnothing = \frac{-1}{10}\sqrt 2$

$cos\ \varnothing = \frac{x}{r}$

$cos\ \varnothing = \frac{-7}{5\sqrt 2}$

Rationalize

$cos\ \varnothing = \frac{-7}{5\sqrt 2} * \frac{\sqrt 2}{\sqrt 2}$

$cos\ \varnothing = \frac{-7*\sqrt 2}{5*2}$

$cos\ \varnothing = \frac{-7\sqrt 2}{10}$

$cos\ \varnothing = \frac{-7}{10}\sqrt 2$

$tan\ \varnothing = \frac{y}{x}$

$tan\ \varnothing = \frac{-1}{-7}$

$tan\ \varnothing = \frac{1}{7}$

$cot\ \varnothing = \frac{x}{y}$

$cot\ \varnothing = \frac{-7}{-1}$

$cot\ \varnothing = 7$

$sec\ \varnothing = \frac{r}{x}$

$sec\ \varnothing = \frac{5\sqrt 2}{-7}$

$sec\ \varnothing = \frac{-5}{7}\sqrt 2$

$csc\ \varnothing = \frac{r}{y}$

$csc\ \varnothing = \frac{5\sqrt 2}{-1}$

$csc\ \varnothing = -5\sqrt 2$

3 0

3 years ago