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dsp73
2 years ago
12

Type the correct answer in each box. Use numerals instead of words. If necessary, use / for the fraction bar.

Mathematics
2 answers:
Alinara [238K]2 years ago
5 0

Answer:

bshshsjsjakskzjjdk

Step-by-step explanation:

ufyftsezutzyeYsucuxit

tankabanditka [31]2 years ago
3 0

Answer:

Step-by-step explanation:

Can you upload another picture?

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FIND the following. Math
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Answer:

Wow you needed help and nobody help, thats mean.

3 0
2 years ago
The weights of bags of ready-to-eat salad are normally distributed with a mean of 300 grams and a standard deviation of 9 grams.
mestny [16]

Answer: 2.5% of the bags weigh less than 282 grams.

Step-by-step explanation: Just took the test and this was the correct answer! :)

8 0
3 years ago
There are 23 classes in the fourth grade. Each grade has 21 students. Write a number sentence that will provide a reasonable est
lapo4ka [179]
23 can round to 20 and 21 can also round to 20 so all u do is 20x20=400 so 400 is your estimated answer
6 0
3 years ago
⦁ In a simple random sample of 1219 US adults, 354 said that their favorite sport to watch is football. Construct a 95% confiden
fomenos

Answer:

95% confidence interval for the proportion of adults in the United States whose favorite sport to watch is football is [0.265 , 0.316].

Step-by-step explanation:

We are given that in a simple random sample of 1219 US adults, 354 said that their favorite sport to watch is football.

Firstly, the pivotal quantity for 95% confidence interval for the proportion of adults in the United States whose favorite sport to watch is football is given by;

        P.Q. = \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } } ~ N(0,1)

where, \hat p = proportion of adults in the United States whose favorite sport to watch is football in a sample of 1219 adults = \frac{354}{1219}

           n = sample of US adults  = 1291

           p = population proportion of adults

<em>Here for constructing 95% confidence interval we have used One-sample z proportion statistics.</em>

So, 95% confidence interval for the population proportion, p is ;

P(-1.96 < N(0,1) < 1.96) = 0.95  {As the critical value of z at 2.5%

                                                    significance level are -1.96 & 1.96}

P(-1.96 < \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } } < 1.96) = 0.95

P( -1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } < {\hat p-p} < 1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } ) = 0.95

P( \hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } < p < \hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } ) = 0.95

<u>95% confidence interval for p</u> = [ \hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } , \hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } ]

                         = [ \frac{354}{1219}-1.96 \times {\sqrt{\frac{\frac{354}{1219}(1-\frac{354}{1219})}{1219} } , \frac{354}{1219}+1.96 \times {\sqrt{\frac{\frac{354}{1219}(1-\frac{354}{1219})}{1219} } ]

                         = [0.265 , 0.316]

Therefore, 95% confidence interval for the proportion of adults in the United States whose favorite sport to watch is football is [0.265 , 0.316].

5 0
3 years ago
Barbara can walk 3,200 meters in 24 meters. Mavis can walk 11,808 feet in 24 minutes. Who walks faster rate of speed? Explain th
grin007 [14]
I used a converter so i put 3200 meters into feet which was 10,498.69 and i rounded it to 10,498 and then i subtract 10,498 feet from 11,808 feet and got 1,310 feet as the answer
4 0
3 years ago
Read 2 more answers
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