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3 years ago

What is 503 subtract 345

Mathematics

2 answers:

snow_tiger [21]3 years ago

7 0

Answer:

158

Step-by-step explanation:

kari74 [83]3 years ago

7 0

Hey there!

503 - 345 = 158

Therefore, the answer is 158

Hope this helps you!

God bless ❤️

xXxGolferGirlxXx

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I WILL GIVE BRAINLIEST

shusha [124]

Answer:

x = -3

Step-by-step explanation:

$y\geq -\frac{2}{3} x-3\\
y\leq 3x+8$

$-\frac{2}{3} x-3=3x+8$

Add 2/3 x to both sides: $-3=\frac{11}{3}x+8$

Subtract 8 from both sides: $-11=\frac{11}{3}x$

Multiply both sides by 3: $-33=11x$

Divide both sides by 11: $x=-3$

Therefore, point of intersection between both lines is at point (-3, -1)

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2 years ago

How do you solve -1x+20 is greater than -7+35

rusak2 [61]

$\huge\fbox{Hello~there!}$

Let's solve this inequality!

$\rm{-x+20>-7+35$

What can we do to solve this inequality? Well, first of all, we can add -7 and 35:

$\rm{-x+20>28$

Now, move 20 to the right, using the opposite operation:

$\rm{-x>28-20$

Subtract:

$\rm{-x>8$

Divide both sides by -1 to isolate x:

$\rm{x$ (Answer)

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<em>Additional comment</em>

When we divide both sides of an inequality by a negative number, we flip the inequality sign.

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I hope you find it helpful.

Feel free to ask if you have any questions.

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3 years ago

Suppose that a factory manufactures only tables and chairs and that the profit on one chair is $15 and on the table is $20. Each

Leya [2.2K]

Answer:

The data we have is:

Profit per chair = $15

Profit per table = $20

Chair needs: 1 large pice, 2 small pieces.

Table needs: 2 large pieces, 2 small pieces.

You have 6 large pieces and 8 small pieces, and you want to maximize the profit.

Let's define:

T = # of tables

C = # of chairs.

Total profit:

P = C*$15 + M*$20

The number of chairs that you can make is given by:

0 ≤ C ≤ 4

If you make 4 chairs, the profit is:

P = 4*$15 = $60

And there will be 2 large pieces left.

Now for the tables.

0 ≤ T ≤ 3

If you make 4 tables, the profit will be:

P = 3*$20 = $60 (same as before)

And there will be two small pieces left.

Then we want to use a medium number of tables and chairs, we can not use the maximum for any of those, the first thing we should try is:

we ideally would want to use all the pieces that we have.

8 small, 6 large:

Then we can make:

2 tables: we use 4 large pieces and 4 small pieces.

T = 2

And we have left 2 large pieces and 4 small pieces.

The leftover is enough to make two chairs.

C = 2.

In this case, where we used all our materials, the profit will be:

P = 2*$15 + 2*$20 = $30 + $40 = $70

The profit is maximized when we make 2 tables and two chairs.

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Answer:

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Step-by-step explanation:

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