Marshall buys a sack of peaches for $5.98. The peaches weigh

Mathematics

1 answer:

kiruha [24]3 years ago

6 0

Answer:

Step-by-step explanation:

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Ms. Tucker travels through two intersections with traffic lights as she drives to the market. The traffic lights operate indepen

sleet_krkn [62]

Answer:

b. 0.45.

Step-by-step explanation:

The total possible outcome of a probability is 1

Given;

Probability that both lights will be red when she reaches them = 0.22

Probability that the first light will be red and the second light will not be red = 0.33

Probability that the second light will be red when she reaches it = x

These are all the possible outcomes, therefore

0.22 + 0.33 + x = 1

0.55 + x = 1

x = 1 - 0.55

x = 0.45

Option b

4 0

3 years ago

PLEASE HELP

poizon [28]

Part A
The given line passes through (-2,2) and it is parallel to the line

$4x - 3y - 7 = 0$

We need to determine the slope of this line by writing it in slope -intercept form.

$3y = 4x - 7$

$y = \frac{4}{3} x - \frac{7}{3}$
The slope of this line is
$\frac{4}{3}$

The line parallel to this line also has slope

$m = \frac{4}{3}$

The equation is

$y = \frac{4}{3} x + c$

We substitute (-2,2)

$2 = \frac{4}{3}( - 2) + c$

$c = 2 + \frac{8}{3} = \frac{14}{3}$

The required equation is

$y = \frac{4}{3} x + \frac{14}{3}$

PART B

The given line is

$4x - 3y - 7 = 0$

The slope of this line is
$\frac{4}{3}$

The slope of the line perpendicular to it is

$m = - \frac{3}{4}$

The equation of the line is

$y = - \frac{ 3}{4} x + c$

We substitute the point, (-2,2)

$2= - \frac{ 3}{4} ( - 2) + c$

$2= \frac{ 3}{2} + c$

$c = 2 - \frac{3}{2} = \frac{1}{2}$

The equation of the perpendicular line is

$y= - \frac{ 3}{4} x + \frac{1}{2}$

6 0

3 years ago

Una comercializadora de café necesita construir una bodega con forma de cubo. La capacidad de la bodega debe ser de 216 metros c

Alexus [3.1K]

Answer:

La arista de la bodega debe medir 6 metros.

Step-by-step explanation:

Podemos encontrar la arista de la bodega sabiendo su volumen:

$V = a^{3}$