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2 years ago

Rewrite each expression in the form kkxxnn, where kk is a real number and nn is an integer. Assume x ≠ 0.

Mathematics

1 answer:

labwork [276]2 years ago

7 0

Answer:

The expression will be $2x^5\times x^{10}=2x^{5+10}=2x^{15}$

Step-by-step explanation:

We have given the expression $2x^5\times x^{10}$

We have to write this expression in kkxxnn form , here kk is real number and nn is integer

We know the property of exponent that when two function are multiplied thn their exponent are added

So $2x^5\times x^{10}=2x^{5+10}=2x^{15}$

Here kk = 2 and nn = 15

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3 years ago

Read 2 more answers

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Marat540 [252]

Answer:

Step-by-step explanation:

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visual:

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2 years ago

consider the equation is Y equals 1/square root of x and y=x-2. approximate solution of the system equations

emmasim [6.3K]

Answer:

$x=1$ and $x=4$

Step-by-step explanation:

We have the following system of equations:

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To solve the problem, we need to equal the two equations:

$x-2=\sqrt{x}$ ⇒ $(x-2)^{2} =x$ ⇒ $x^{2} -4x + 4 = x$

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So you need to find two numbers that added equal to 5 and multiplied equal to 4. These two numbers are $x=-1$ and $x=-4$ .

Then, the factorized form of the polynomial is: $(x-1)(x-4)$ .

The, the solution to the system of equations is: $x=1$ and $x=4$ .

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3 years ago

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2 years ago

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Tpy6a [65]

D
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