They where connected to the history of N-Words
Control and Experimental groups alcohol on reaction
Osmosis is the net movement of water molecules through a semi-permeable memberane from a region of higher water potential to a region of lower water potential.
so in the first case, since 10% of sucrose solution has a lower water potential than the pure water, so water molecules will flow into the sac, causing the sac to increase in volume. note that sucrose molecules can't diffuse out since there's a semi-permeable membrane.
in the question, I'm not 100% sure what the "sac solution" is meant by, but I guess it's the solution inside the sac
so here if the sac sucrose is 20%, the concentration of water is larger in difference than the first time, so osmosis rate will increase.
but if the "sac solution" is meant by replacing the water of the first case, then the sac inside would have a higher water potential, as the sucrose concentration is more diluted. then the water molecules will flow from the sac back to the beaker or whatever container it is.
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Answer:
double a;
double b;
double distance = Math.sqrt( (Math.pow(a, 2) + Math.pow(b, 2));
System.out.println("The distance is: " + distance);
Explanation:
The code snippet is written in Java.
First, variable a is declared as a type of double and variable b is also declared as a type of double.
The given formula for the distance is:
√(a² + b²)
So we use the inbuilt function of Java to calculate the power and the square root.
Math.sqrt is to find the square root and it returns a value of type double.
Math.pow is use to calculate the value of a² and b².
a² = Math.pow(a, 2)
b² = Math.pow(b, 2)
Then Math.sqrt is applied to the sum of Math.pow(a, 2) and Math.pow(b, 2), the value is assigned to distance of type double.
The value of distance is now displayed to the user:
System.out.println("The distance is: " + distance);
