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cluponka [151]
3 years ago
6

Cuales son los accesorios electronicos mas recomendados?

Computers and Technology
1 answer:
Aleonysh [2.5K]3 years ago
7 0
Los i-phone y iPad. Esto porque son los más rápidos y te los puedes traer a más lugares.
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What does the internet engineering task force (IEFT) do?
Anvisha [2.4K]

The Internet Engineering Task Force is the premier internet standard body that defines standard internet protocols like TCP/IP. It is a large community that consists of operators, network designers, researchers and vendors drawn from the internet society’s individual and organization bodies and is concerned with the evolution and the smooth operation of the internet.

7 0
3 years ago
Which address correctly represents one that is composed of two halves, one assigned to a network adapter manufacturer, and the o
Vlad1618 [11]
 Media access control address
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3 years ago
In python please:
Vikki [24]

Answer:

"

if 'marsupial' in dictionary:

   del dictionary['marsupial']

else:

   print("The key marsupial is not in the dictionary")

"

Explanation:

So you can use the keyword "in" to check if a certain key exists.

So the following code:

"

if key in object:

   # some code

"

will only run if the value of "key" is a key in the object dictionary.

So using this, we can check if the string "marsupial' exists in the dictionary.

"

if 'marsupial' in dictionary:

   # code

"

Since you never gave the variable name for the variable that references a dictionary, I'm just going to use the variable name "dictionary"

Anyways, to delete a key, there are two methods.

"

del dictionary[key]

dictionary.pop(key)

"

Both will raise the error "KeyError" if the key doesn't exist in the dictionary, although there is method with pop that causes an error to not be raised, but that isn[t necessary in this case, since you're using the if statement to check if it's in the dictionary first.

So I'll just use del dictionary[key] method here

"

if 'marsupial' in dictionary:

   del dictionary['marsupial']

else:

   print("The key marsupial is not in the dictionary")

"

The last part which I just added in the code is just an else statement which will only run if the key 'marsupial' is not in the dictionary.

3 0
2 years ago
? Assessment
Ksivusya [100]

Answer:

Her performance over the course of  a season.

Explanation:

An athlete is signed for a season. These days each aspect of an athlete is noted through the effective use of the best technology. However, for detailed study, one or several plays, and certainly not the second half of a game is enough. It's required to collect the details for a complete season. And that is possible, as an athlete is hired for a season. And through such a detailed data set of a complete season, we can now train a machine as well, and it will let the athlete know where she is going wrong. And thus she can improve and remove those faults from her game, and become a better athlete. And even for a coach, one complete season is required, though when he has not seen her playing before that season. It's assumed that this is her first season. All the options mentioned are good, but the best is certainly the one with complete details, and that is a complete season. The rest is good but not the best.

4 0
3 years ago
[30 points, will mark Brainliest] Which of the following is the lowest hexadecimal value? Explain why. Options to chose; F2, 81,
larisa86 [58]

Answer:

The answer to this question is given below in the explanation section.

Explanation:

First, we need to convert these hexadecimal numbers into decimal numbers, then we can easily identify which one is the lowest hexadecimal.

The hexadecimal numbers are F2, 81, 3C, and 39.

F2 = (F2)₁₆ = (15 × 16¹) + (2 × 16⁰) = (242)₁₀

81 = (81)₁₆ = (8 × 16¹) + (1 × 16⁰) = (129)₁₀

3C = (3C)₁₆ = (3 × 16¹) + (12 × 16⁰) = (60)₁₀

39 = (39)₁₆ = (3 × 16¹) + (9 × 16⁰) = (57)₁₀

The 39 is the lowest hexadecimal number among the given numbers.

Because 39 hex is equal to 57 decimal.

39 = (39)₁₆ = (3 × 16¹) + (9 × 16⁰) = (57)₁₀

5 0
3 years ago
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