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ICE Princess25 [194]
4 years ago
9

Can you figure out the missing number in this sequence? Type your answer below!

Mathematics
1 answer:
Artemon [7]4 years ago
4 0

Answer:

731`55

Step-by-step explanation:

*Step-by-step explanation:*

The given sequence:

88511, 16351, ?, 10251

To find, the missing number (?) = ?

The pattern follow:

1. To Add the first 2 digits in the number .

2. Subtract digit 3 from Digit 2 .

3. The multiply digit 3 and 4 .

4. To  divide digit 4 by 3.

16351 ⇒ 8 + 8 = 16,   8 - 5 = 3, 5 × 1 = 5 and \dfrac{1}{1} =111=1

= 16351

? ⇒ 1 + 6 = 7, 6 - 3 = 3, 3 × 5 = 15 and \dfrac{5}{1}15 = 5

= 73155

10251  ⇒ 7 + 3 = 10, 3 - 1 = 2,  1 × 5 = 5 and \dfrac{5}{5}55 = 1

=  10251

∴ The missing number of the given sequence = 73155

Thus, the missing number of the given sequence is 73155.

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a triangular shape has an area of 70 square inches the height is 8 and three fourths write and solve an equation to find the len
Gala2k [10]
Area formula of a triangle is:
A = \frac{1}{2} bh
We know the area and the height, so substitute to find the base

A = 70 m²
h = 8.75 m or 8 \frac{3}{4} m  (its the same thing)

70 = \frac{1}{2} × b × 8.75
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Divide by 4.375 on either sides to isolate b
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(10 pts) A four-lane freeway (two lanes in each direction) is located on rolling terrain and has 12-ft lanes, no lateral obstruc
dimulka [17.4K]

Answer:

309

Step-by-step explanation:

To determine the estimated free-flow speed

FFS = 75.4 -f_{LW}-f_{LC} - 3.22 TRD^{0.84}

From the table "Adjustment for lane width," which corresponds to a lane width of 12 feet. As a result, f_{LW} equals 0 mi/h.

Take the meaning from the table "Adjustment for right-shoulder lateral clearance," which corresponds to 6 feet of right shoulder lateral clearance and two lanes in one direction.

The f_{LC} = 0 mi/h

FFS = 75.4 -0-0-3.22 ( \dfrac{5}{6})^{0.84}

= 72.64 \ mi/h

\simeq  73 \ mi/h

Determine the peak-hour factor

PHF = \dfrac{V}{V_{15}\times 4} \\ \\ =\dfrac{1800}{700\times 4}\\ \\ = 0.6429

Now, Find the heavy-vehicle adjustment factor.

v_P = \dfrac{V}{PHF\times N \times f_{HV}\times f_P} --- (1)

Take the value for the 15-minute passenger car equivalent flow rate from the table "LOS requirements for freeway segments" for the FFS and LOS C conditions. The free-flow speed is estimated to be 73 miles per hour

v_p = 1735+ \dfrac{73-70}{75-70}(1775-1735)

v_p = 1759 \ pc/h/In

Think about for familiar users the value of f_p = 1.00

Replace all of the values obtained in (1)

v_p = \dfrac{V}{PHF \times N\times f_{HV}\times f_p}

1759 = \dfrac{1800}{0.6429\times 2 \times f_{HV}\times 1}

f_{HV} = \dfrac{1800}{0.6429\times 2 }\times \dfrac{1}{1759}

= 0.795

Calculate the percentage of trucks and buses in the flow of traffic stream.

f_{HV} = \dfrac{1}{1+P_{\tau}(E_{\tau}-1) + P_R(E_R-1)}

Take the values from the table "Passenger car equivalent for extended highway segments" referring to trucks and buses and rolling terrains for passenger car equivalent for trucks and buses and recreational vehicles. As a result, E_T has a value of 2.5 and E_R has a value of 2.0.

Since P_R is zero and there is no recreational vehicle.

Then;

0.759 = \dfrac{1}{1+ P_T(2.5 -1) +0}

P_T = 0.1719

Finally, to estimate the maximum number of large trucks and buses; we have:

= V\times P_T = 1800 \times 0.1719

Maximum number of large trucks and buses = 309

4 0
3 years ago
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