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3 years ago

Can you figure out the missing number in this sequence? Type your answer below!

Mathematics

1 answer:

Artemon [7]3 years ago

4 0

Answer:

731`55

Step-by-step explanation:

*Step-by-step explanation:*

The given sequence:

88511, 16351, ?, 10251

To find, the missing number (?) = ?

The pattern follow:

1. To Add the first 2 digits in the number .

2. Subtract digit 3 from Digit 2 .

3. The multiply digit 3 and 4 .

4. To divide digit 4 by 3.

16351 ⇒ 8 + 8 = 16, 8 - 5 = 3, 5 × 1 = 5 and \dfrac{1}{1} =111=1

= 16351

? ⇒ 1 + 6 = 7, 6 - 3 = 3, 3 × 5 = 15 and \dfrac{5}{1}15 = 5

= 73155

10251 ⇒ 7 + 3 = 10, 3 - 1 = 2, 1 × 5 = 5 and \dfrac{5}{5}55 = 1

= 10251

∴ The missing number of the given sequence = 73155

Thus, the missing number of the given sequence is 73155.

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What is the solution to the system of equations? y=-5+3, y=1

andrew11 [14]

Answer:

x = 2/5 and y =1 (2/5, 1)

Step-by-step explanation:

I will assume that you meant y = -5x + 3. If that's the case, then we equate

y = -5x + 3 to y = 1, obtaining:

-5x = -2, so that x = 2/5 and y =1.

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3 years ago

How many groups of sixty are in two hundred forty-four

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The answer to this question is 4 groups.

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3 years ago

Read 2 more answers

List the next four multiples of fraction 7/12

Sidana [21]

<h2>Hello!</h2>

The answer is:

$\frac{14}{12}=\frac{7}{12}*2\\\\\\\frac{21}{12}=\frac{7}{12}*3\\\\\\\\\frac{28}{12}=\frac{7}{12}*4\\\\\\\\\frac{35}{12}=\frac{7}{12}*5$

A multiple of a number is the repeated sum of itself, for example:

Multiple of the number 1 are: 1, 2, 3, 4, 5 and so...

Multiple of the number 3 are: 3, 6, 9, 12, 15 and so...

From the example we have:

Multiple of the number 3 are: Itself, (3+3), (3+3+3), (3+3+3+3), (3+3+3+3+3) and so...

So,

Multiple of $\frac{7}{12}$ are:

$\frac{14}{12}=\frac{7}{12}*2=\frac{7}{12}+\frac{7}{12}\\\\\\\frac{21}{12}=\frac{7}{12}*3=\frac{7}{12}+\frac{7}{12}+\frac{7}{12}\\\\\\\\\frac{28}{12}=\frac{7}{12}*4=\frac{7}{12}+\frac{7}{12}+\frac{7}{12}+\frac{7}{12}\\\\\\\\\frac{35}{12}=\frac{7}{12}*5=\frac{7}{12}+\frac{7}{12}+\frac{7}{12}+\frac{7}{12}+\frac{7}{12}$

Have a nice day!

6 0

3 years ago

A bag contains 8 black beads and 4 white beads. If 2 beads are drawn at random, what is the probability that both beads are blac

maria [59]

Answer:

14/33

Step-by-step explanation:

The total amount of beads is 8+4 = 12. 8 of these are black beads, so that is what we want, so 8/12 or 2/3. For the second one, one black bead is already taken so 8-1 = 7 are left and for the total 12 - 1 = 11 are left, so 7/11. Multiply this by 2/3 and we get 14/33.

3 0

3 years ago

Which ordered pair is a solution of the system ?

drek231 [11]

Hello!

Since we already see an equation that equals y (-2x-4), we can plug that equation into the first to solve for x.

x+4(-2x-4)=19
x-8x-16=19
-7x=35
x=-5

Now that we know the value of x, we will plug it into the second equation to solve for y.

y=-2(-5)-4
y=10=4
y=6

This gives us the answer below

$\left \{ {{x=-5} \atop {y=6}} \right.$

The correct answer is A) (-5,6)

I hope this helps!

7 0

3 years ago