Given a right cone with radius rand slant height s, what does the formula irs

CINDY IS A HOSTESS AT A COUNTRY CLUB

stich3 [128]

Answer and Step-by-step explanation:

Add together the hours, then divide the amount earned by the total amount of hours.

3 + 5 = 8

105 ÷ 8 = $13.125 (which would round up to 13.13) [About $13.13] is earned per hour.

#teamtrees #PAW (Plant And Water)

5 0

3 years ago

Franco has $265.87 in his checking account. Then he writes the deposit slip shown. How should Franco enter the deposit in his ch

artcher [175]

Answer:

The answer is the top right one since the total $96.35 is on the deposit side.

( i did this before and got it right btw)

8 0

3 years ago

Which values for x and y make the statement (x + 5)(y - 6) = 0 true?

-BARSIC- [3]

$||Solving \ for \ x. ||$ 

$(x + 5)(y - 6) = 0$

$(x + 5)(y - 6) = 0 :x$

$
x+5=0
 
$ $|Divide \ both \ sides \ by \ y-6|$

$
x=-5
 
$ $|Subtract \ 5 \ from \ both \ sides|$

$||Solving \ for \ y. ||$

$
y-6=0
 
$ $|Divide \ both \ sides \ by \ x+5|$

$
y=6
 
$

$Solution =\ \textgreater \ x = -5, y = 6$

6 0

3 years ago

3√75 simplest rationalizing factor PLEASE DO ANSWER ONLY IF YOU KNOW IT

rjkz [21]

Answer:

the square root of 75 is 8.6

and 8.6 times 3 is

the answer is 25.8

Hope This Helps!!!

4 0

3 years ago

The mean number of words per minute (WPM) read by sixth graders is 8888 with a standard deviation of 1414 WPM. If 137137 sixth g

Bingel [31]

Noticing that there is a pattern of repetition in the question (the numbers are repeated twice), we are assuming that the mean number of words per minute is 88, the standard deviation is of 14 WPM, as well as the number of sixth graders is 137, and that there is a need to estimate the probability that the sample mean would be greater than 89.87.

Answer:

"The probability that the sample mean would be greater than 89.87 WPM" is about $\\ P(z>1.56) = 0.0594$ .

Step-by-step explanation:

This is a problem of the distribution of sample means. Roughly speaking, we have the probability distribution of samples obtained from the same population. Each sample mean is an estimation of the population mean, and we know that this distribution behaves normally for samples sizes equal or greater than 30 $\\ n \geq 30$ . Mathematically

$\\ \overline{X} \sim N(\mu, \frac{\sigma}{\sqrt{n}})$ [1]

In words, the latter distribution has a mean that equals the population mean, and a standard deviation that also equals the population standard deviation divided by the square root of the sample size.

Moreover, we know that the variable Z follows a normal standard distribution, i.e., a normal distribution that has a population mean $\\ \mu = 0$ and a population standard deviation $\\ \sigma = 1$ .

$\\ Z = \frac{\overline{X} - \mu}{\frac{\sigma}{\sqrt{n}}}$ [2]

From the question, we know that

The population mean is $\\ \mu = 88$ WPM
The population standard deviation is $\\ \sigma = 14$ WPM

We also know the size of the sample for this case: $\\ n = 137$ sixth graders.

We need to estimate the probability that a sample mean being greater than $\\ \overline{X} = 89.87$ WPM in the distribution of sample means. We can use the formula [2] to find this question.

The probability that the sample mean would be greater than 89.87 WPM

$\\ Z = \frac{\overline{X} - \mu}{\frac{\sigma}{\sqrt{n}}}$

$\\ Z = \frac{89.87 - 88}{\frac{14}{\sqrt{137}}}$

$\\ Z = \frac{1.87}{\frac{14}{\sqrt{137}}}$

$\\ Z = 1.5634 \approx 1.56$

This is a standardized value and it tells us that the sample with mean 89.87 is 1.56 standard deviations above the mean of the sampling distribution.

We can consult the probability of P(z<1.56) in any cumulative standard normal table available in Statistics books or on the Internet. Of course, this probability is the same that $\\ P(\overline{X} < 89.87)$ . Then

$\\ P(z$

However, we are looking for P(z>1.56), which is the complement probability of the previous probability. Therefore

$\\ P(z>1.56) = 1 - P(z$

$\\ P(z>1.56) = P(\overline{X}>89.87) = 0.0594$

Thus, "The probability that the sample mean would be greater than 89.87 WPM" is about $\\ P(z>1.56) = 0.0594$ .

5 0

3 years ago