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3 years ago

Factoring the GCMF of 12y-16

Mathematics

1 answer:

deff fn [24]3 years ago

6 0

<h2>The factoring the GCMF of 12y - 16 = 4(3y - 4)</h2>

Step-by-step explanation:

We have,

12y - 16

To find, the factoring of GCMF of 12y - 16 = ?

∴ 12y - 16

The factors of 12 = 1, 2, 3, 4, 6 and 12 and

The factors of 16 = 1, 2, 4, 8 and 16

The greatest common multiple factor(GCMF) = 4

12y - 16

= 4(3y - 4)

∴ The factoring the GCMF of 12y - 16 = 4(3y - 4)

Thus, the factoring the GCMF of 12y - 16 is 4(3y - 4).

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2 − 10n = 2 + 4n<br> What does n equal?

tiny-mole [99]

Answer:

0 =n

Step-by-step explanation:

2 − 10n = 2 + 4n

Add 10n to each side

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Subtract 2 from each side

2-2 = 2+16n-2

0 = 16n

Divide each side by 16

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Answer:

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2 years ago

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Answer:

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Rewrite in Polar Form....<br> x^(2)+y^(2)-6y-8=0

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$\bf x^2+y^2-6y-8=0\qquad 
\begin{cases}
x^2+y^2=r^2\\\\
y=rsin(\theta)
\end{cases}\implies r^2-6rsin(\theta)=8
\\\\\\
\textit{now, we do some grouping}\implies [r^2-6rsin(\theta)]=8
\\\\\\\
[r^2-6rsin(\theta)+\boxed{?}^2]=8\impliedby 
\begin{array}{llll}
\textit{so we need a value there to make}\\
\textit{a perfect square trinomial}
\end{array}$

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\\\\\\
\textit{now, bear in mind we're just borrowing from zero, 0}
\\\\
\textit{so if we add, \underline{whatever}, we also have to subtract \underline{whatever}}$

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\left. \qquad \right.\uparrow \\
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3 years ago