Let w represent the width of the rectangle in cm. Then its length in cm is (3w+9). The perimeter is the sum of two lengths and two widths, so is ...
... 418 = 2(w + (3w+9))
... 209 = 4w +9 . . . . . . divide by 2, collect terms
... 200 = 4w . . . . . . . . subtract 9
... 50 = w . . . . . . . . . . divide by 4
... length = 3w+9 = 3·50 +9 = 159
The dimensions of this piece of land are 159 cm by 50 cm.
Answer:
14,28,42 and 56
Step-by-step explanation:
Multiply all lengths by 2 as the quadrilateral is dilated by a scale factor of 2
Ok can you please show the formula or give more information please
Answer:
x = -1
Step-by-step explanation:
Add 4x to each side of the equation
Subtract ⅚ from each side
Divide both sides by -5