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2 years ago

Help me please. either one is fine.

Mathematics

1 answer:

mestny [16]2 years ago

6 0

7)
95+(3x+23)+(7x-4)+(9x-6)+90 = (5-2) x 180
x = 18

9)
41+(3x+6)+(7x-11)+62+(4x+7)+(6x-5) = 360
x = 13

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One golfer's scores for the season are 88, 90, 86, 89, 96, and 85. Another

Allisa [31]

Mean of the first golfer = 89

Mean of the second golfer = 87

Range of the first golfer = 11

Range of the second golfer = 8

Explanation:

First golfer scores 88, 90, 86, 89, 96 and 85.

Sum of the scores of first golfer = 88 + 90 + 86 + 89 + 96 + 85 = 534

Number of observation of first golfer = 6

$\text {Mean} = \frac{\text {Sum of the observation}}{\text {Number of observation}}$

Mean of the first golfer = $\frac{534}{6}=89$

Mean of the first golfer = 89

Range of the first golfer = Highest score – Lowest score

= 96 – 85

Range of the first golfer = 11

Second golfer scores 91, 86, 88, 84, 90 and 83.

Sum of the scores of second golfer = 91 + 86 + 88 + 84 + 90 + 83 = 522

Number of observation of second golfer = 6

$\text {Mean} = \frac{\text {Sum of the observation}}{\text {Number of observation}}$

Mean of the second golfer = $\frac{522}{6}=87$

Mean of the second golfer = 87

Range of the second golfer = Highest score – Lowest score

= 91 – 83

Range of the second golfer = 8

Comparing the golfer's skills:

Mean of first golfer is greater than Mean of second golfer. (i.e. 89 > 87)

Range of first golfer is greater than Range of second golfer. (i.e. 11 > 8)

Thus, first golfer have more skills than second golfer.

6 0

3 years ago

The manufacturer of the ColorSmart-5000 television set claims 95 percent of its sets last at least five years without needing a

patriot [66]

Answer:

Step-by-step explanation:

Hello!

Your study variable is X: "number of ColorSmart-5000 that didn't need repairs after 5 years of use, in a sample of 390"

X~Bi (n;ρ)

ρ: population proportion of ColorSmart-5000 that didn't need repairs after 5 years of use. ρ = 0.95

n= 390

x= 303

sample proportion ^ρ: x/n = 303/390 = 0.776 ≅ 0.78

Applying the Central Limit Theorem you approximate the distribution of the sample proportion to normal to obtain the statistic to use.

You are asked to estimate the population proportion of televisions that didn't require repairs with a confidence interval, the formula is:

^ρ± $Z_{1-\alpha /2}$ * √[(^ρ(1-^ρ))/n]

$Z_{1-\alpha /2}$ = $Z_{0.995}$ = 2.58

0.78±2.58* √[(0.78(1-0.78))/390]

0.0541

[0.726;0.834]

With a confidence level of 99% you'd expect that the interval [0.726;0.834] contains the true value of the proportion of ColorSmart-5000 that didn't need repairs after 5 years of use.

I hope it helps!

7 0

3 years ago

Which of the following would best represent a cosine function with an amplitude of 3, a period of pi/2 , and a midline at y = –4

Grace [21]

To transform the function $f(x)= cos(x)$ to have the amplitude of 3, we need to multiply the constant 3 to the function f(x), so we have $y=3f(x)$

To transform the function $f(x)=cos(x)$ to have the midline $y=-4$ we need to subtract $f(x)$ by 4, so we have $y=f(x)-4$ ,

To transform the function $f(x)=cos(x)$ to have period of $\frac{ \pi }{2}$ , we need to divide the original period $2 \pi$ by 4, so we have $y=f(4x)$ . Note that it is the $4x$ gives the effect of dividing the points on x-axes by 4 and the period is read on x-axes

Hence, the full transformation is given $y=3f(4x)-4$ which is the last option