We have been given that the test scores on a final exam are normally distributed with a mean of 74 and a standard deviation of 3. We are asked to find the probability that a randomly selected test has a score higher than 77.
First of all, we will find z-score corresponding to sample score 77.
, where,
z = z-score,
x = Random sample score,
= Mean,
= Standard deviation.
Now we need to find .
We will use formula to find the probability greater than a z-score of 1.
Using normal distribution table, we will get:
Therefore, the probability that a randomly selected test has a score higher than 77 would be 0.15866.
Answer:
The value of X is 62 degrees
Step-by-step explanation:
The arc length L of a circle is given by formula:
L= 2(pi)(r)X / 360 (1)
where pi = 3.14, r is the radius of the circle and X the angle that produces the arc. You want the angle X so we can simplify X in equation (1)
360L=2(pi)(r)X
360L/2(pi)(r)= X
X = 360L/2(pi)(r)
We replace the radius r=9cm the arc L = 9.7 cm and pi and obtain
X = 360* (9.7 cm)/ 2(3.14)*(9cm) = 3492/56.52 = 61.78
That rounded to nearest degree is 62 degrees.
Answer:
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