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3 years ago

5

A bakery used 25% more butter this month than last month. If the bakery used 240 kilograms of butter last month, how much did it

use this month?

1 answer:

gulaghasi [49]3 years ago

3 0

Answer:

30

Step-by-step explanation:

First multiply 240 by 25% then add that value back to 240.

240 x 25% = 60

240+60 = 300

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Write 3 1/8% as fraction in simplest form

PolarNik [594]

so change a value to a percentage format, we simply divide it by 100.

for example, 2% can be rewritten as 2/100 or 0.02 in decimal format.

now, let's first convert the mixed fraction to improper, and then do the percentage format and simplification.

$\bf \stackrel{mixed}{3\frac{1}{8}}\implies \cfrac{3\cdot 8+1}{8}\implies \stackrel{improper}{\cfrac{25}{8}} \\\\[-0.35em] ~\dotfill\\\\ \cfrac{~~\frac{25}{8}~~}{100}\implies \cfrac{~~\frac{25}{8}~~}{\frac{100}{1}}\implies \cfrac{25}{8}\cdot \cfrac{1}{100}\implies \cfrac{1}{8}\cdot \cfrac{25}{100}\implies \cfrac{1}{8}\cdot \cfrac{1}{4}\implies \cfrac{1}{32}$

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3 years ago

PLEASE HELP Given: △KLM LM=12, m∠K=60°, m∠M=45° Find: Perimeter of △KLM.

worty [1.4K]

We have to find the perimeter of the triangle KLM.

We have been given that the length of the side LM=12, $m\angleK=60^\circ$ , and $m\angle M= 45^\circ$

Refer the attached image.

In a triangle sum of three angles should be $180^\circ$ .

So,

$m\angle K+m\angle L+m\angle M=180^\circ$

Plugging the values of angle K and angle M, we get:

$60^\circ+m\angle L+45^\circ=180^\circ$

So,

$m\angle L=180^\circ-105^\circ=75^\circ$

Now, that we have the measure of angle L, we will apply sine rule to find the length of the sides KL and KM.

Using the sine law for the triangle KLM, we get:

$\frac{sin K}{LM}=\frac{sin L}{KM}=\frac{sin M}{KL}$

Refer the image. Plugging the value of the sides of the triangle KLM and the angles of the triangle KLM, we get:

$\frac {sin 60^\circ}{12}=\frac{sin 75^\circ}{y}=\frac{sin 45^\circ}{x}$

Now using,

$\frac {sin 60^\circ}{12}=\frac{sin 75^\circ}{y}$

We get the value of 'y'

$y=\frac{sin 75^\circ}{sin 60^\circ} \times 12=\frac{0.9659}{0.866} \times 12=13.38$

So the length of the side KM is 13.38 units.

Now using,

$\frac {sin 60^\circ}{12}=\frac{sin 45^\circ}{x}$

We get the value of 'x'

$x=\frac{sin 45^\circ}{sin 60^\circ} \times 12=\frac{0.707}{0.866} \times 12=9.79$

So the length of the side KL is 9.79 units.

Now, to find the perimeter of the triangle KLM we need to sum up the length of the sides of the triangle KLM.

The perimeter of the triangle KLM $= KL+ LM + KM = 9.79 + 12 + 13.38 = 35.17$ units

6 0

3 years ago

Read 2 more answers

Given the quadratic equation ax²-5b+4a=0, where a and b are constants has two real an equal roots,find a:b

sergiy2304 [10]

Answer:

Therefore either a:b = 5:4 or a:b=-5:4

Step-by-step explanation:

ax²-5bx+4a=0

Since the quadratic equation has two real root.

Then b²-4ac>0

Here a= a , b= -5b and c=4a

∴(-5b)²-4.a.4a=0

⇔25b²=16a²

⇔5b=±4a

$\Leftrightarrow \frac{a}{b} =\pm\frac{5}{4}$

Therefore either a:b = 5:4 or a:b=-5:4

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3 years ago

Please help me out on this question

zavuch27 [327]

729-243=486

486×3=1458

1458+729=2187(x=7)

1458×3=4374

4374+2187=6561(x=8)

4374×3=13122(average rate of change for interval 8 to 9)

13122+6561=19683(x=9)

Ans: B

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3 years ago

The rate at which an airplane flew was StartFraction 700 miles over 2 hours EndFraction. How can the unit rate be determined?

disa [49]

Answer:

C

Step-by-step explanation:

dont remember how I did it but it is right.

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3 years ago

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