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Furkat [3]
2 years ago
11

2/3 Divided by 1/4.

Mathematics
2 answers:
Lynna [10]2 years ago
6 0

Answer:

2.66

Step-by-step explanation:

2.66

son4ous [18]2 years ago
4 0

Answer:

8/3, or 2 2/3

Step-by-step explanation:

2/3 divided by 1/4 is equal to multiplying 2/3 by 1/4's reciprocal.

2/3x4/1

2x4=8, our numerator

3x1=3, our denominator

8/3 is equal to 2 2/3

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What is the greatest common factor of 30, 48, and 2?
arlik [135]

Answer:

<h3>The greatest common factor of 30, 48 and 2 is 2</h3>

Step-by-step explanation:

<h2>I HOPE IT HELPS </h2>
7 0
3 years ago
in circle F, points A,B,C,D, and E are located on the circle such that measure of C=119°, and BE is perpendicular AD. determine
VLD [36.1K]

Answer:

Measure of arc AE = 58°

Step-by-step explanation:

As shown: ABCD is a quadrilateral, ∠C = 119°

So, ∠C + ∠A = 180°

∴ ∠A = 180° - ∠C = 180° - 119° = 61°

ΔAGB is a right triangle at G

So, ∠A + ∠B = 90°

∴ ∠ABG = 90 - ∠A = 90 - 61 = 29°

Arc AE opposite to the angle ∠ABG

So, measure of arc AE = 2∠ABG = 2 * 29° = 58°

6 0
3 years ago
Let A, B, C and D be sets. Prove that A \ B and C \ D are disjoint if and only if A ∩ C ⊆ B ∪ D
ANEK [815]

Step-by-step explanation:

We have to prove both implications of the affirmation.

1) Let's assume that A \ B and C \ D are disjoint, we have to prove that A ∩ C ⊆ B ∪ D.

We'll prove it by reducing to absurd.

Let's suppose that A ∩ C ⊄ B ∪ D. That means that there is an element x that belongs to A ∩ C but not to B ∪ D.

As x belongs to A ∩ C, x ∈ A and x ∈ C.

As x doesn't belong to B ∪ D, x ∉ B and x ∉ D.

With this, we can say that x ∈ A \ B and x ∈ C \ D.

Therefore, x ∈ (A \ B) ∩ (C \ D), absurd!

It's absurd because we were assuming that A \ B and C \ D were disjoint, therefore their intersection must be empty.

The absurd came from assuming that A ∩ C ⊄ B ∪ D.

That proves that A ∩ C ⊆ B ∪ D.

2) Let's assume that A ∩ C ⊆ B ∪ D, we have to prove that A \ B and C \ D are disjoint (i.e.  A \ B ∩ C \ D is empty)

We'll prove it again by reducing to absurd.

Let's suppose that  A \ B ∩ C \ D is not empty. That means there is an element x that belongs to  A \ B ∩ C \ D. Therefore, x ∈ A \ B and x ∈ C \ D.

As x ∈ A \ B, x belongs to A but x doesn't belong to B.  

As x ∈ C \ D, x belongs to C but x doesn't belong to D.

With this, we can say that x ∈ A ∩ C and x ∉ B ∪ D.

So, there is an element that belongs to A ∩ C but not to B∪D, absurd!

It's absurd because we were assuming that A ∩ C ⊆ B ∪ D, therefore every element of A ∩ C must belong to B ∪ D.

The absurd came from assuming that A \ B ∩ C \ D is not empty.

That proves that A \ B ∩ C \ D is empty, i.e. A \ B and C \ D are disjoint.

7 0
3 years ago
Last year, lien earned 1200 more than her husband. Together they earned 45,200. How much did each of them earn?
d1i1m1o1n [39]

Answer:

Lien earned $23,800

Husband earned $22,600

Step-by-step explanation:

$45,200 divide it by 2 = $22,600

then you add $1,200 to $22,600 and get  $23,800

4 0
3 years ago
What is the completely factored form of x^4y-4x^2y-5y
AnnZ [28]

Answer:

y(x^2+1)(x^2-5)

Step-by-step explanation:

Factor the expression by first finding a GCF. Each term has the y variable and this can be pulled out as the GCF.

x^4y-4x^2y-5y\\y(x^4-4x^2-5)

To further factor the expression break the polynomial into two binomials.

To factor into two binomials, find factors that multiply to -5 and add to -4.

-5 and 1 are factors and these make the binomials (x^2+1)(x^2-5).

The final factorization is y(x^2+1)(x^2-5)

3 0
3 years ago
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