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Annette [7]
3 years ago
12

The length of a diagonal of a square is 35√2 millimeters. find the perimeter of the square

Mathematics
1 answer:
Volgvan3 years ago
4 0

Answer:

i dk sorry

Step-by-step explanation:

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Vanilla 15 and chocolate is 20
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What is the sum of the first five terms of a geometric series with a1 =20 and r =1/4?
drek231 [11]
The sum of the first n terms in a geometric sequence given the first term (a1) and the common ratio (r) is calculated through the equation,

                            <span>Sn </span>= (<span><span><span>a1</span>(1−<span>r^n</span>) / (</span><span>1−r)

Substituting the known terms,
                           Sn = (20)(1 - (1/4)^4)) / (1 - 1/4)
                           Sn = 26.5625

Thus, the sum of the first four terms is 26.5625. </span></span>
5 0
3 years ago
which has a greater effect on the volume - changing the radius by a given amount or changing the height by the same amount/ why?
AURORKA [14]
Assuming we’re talking about a cylinder, whose volume formula is V = pi r^2 h…

It will have a greater effect to change a variable’s value that has a greater power on it.

Changing h from 1 to 2 doubles the volume.
Changing r from 1 to 4 quadruples the volume, because 1^2 = 1 and 2^2 = 4. The effect of the change on r is amplified by the power.
3 0
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5 0
3 years ago
A large electronic office product contains 2000 electronic components. Assume that the probability that each component operates
KIM [24]

Answer:

The probability is 0.971032

Step-by-step explanation:

The variable that says the number of components that fail during the useful life of the product follows a binomial distribution.

The Binomial distribution apply when we have n identical and independent events with a probability p of success and a probability 1-p of not success. Then, the probability that x of the n events are success is given by:

P(x)=\frac{n!}{x!(n-x)!}*p^{x}*(1-p)^{n-x}

In this case, we have 2000 electronics components with a probability 0.005 of fail during the useful life of the product and a probability 0.995 that each component operates without failure during the useful life of the product. Then, the probability that x components of the 2000 fail is:

P(x)=\frac{2000!}{x!(2000-x)!}*0.005^{x}*(0.995)^{2000-x}     (eq. 1)

So, the probability that 5 or more of the original 2000 components fail during the useful life of the product is:

P(x ≥ 5) = P(5) + P(6) + ... + P(1999) + P(2000)

We can also calculated that as:

P(x ≥ 5) = 1 - P(x ≤ 4)

Where P(x ≤ 4) = P(0) + P(1) + P(2) + P(3) + P(4)

Then, if we calculate every probability using eq. 1, we get:

P(x ≤ 4) = 0.000044 + 0.000445 + 0.002235 + 0.007479 + 0.018765

P(x ≤ 4) = 0.028968

Finally, P(x ≥ 5) is:

P(x ≥ 5) = 1 - 0.028968

P(x ≥ 5) = 0.971032

3 0
3 years ago
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