In one revolution of the wheel, a point on the edge travels a distance equal to the circumference of the wheel.
The wheel has radius 1 ft, so its circumference is 2π (1 ft) = 2π ft.
Then the point has a linear speed of
(1/4 rev/s) * (2π ft/rev) = 2π/4 ft/s = π/2 ft/s
Use Multiplication Distribute Property: (xy)^a = x^ay^a
6^2(x^-2)^2(0.5x)^4
Simplify 6^2 to 36
36(x^-2)^2(0.5x)^4
Use this rule: (x^a)^b = x^ab
36x^-4(0.5x)^4
Use the Negative Power Rule: x^-a = 1/x^a
36 × 1/x^4(0.5x)^4
Use the Multiplication Distributive Property: (xy)^a = x^ay^a
36 × 1/x^4 × 0.5^4x^4
Simplify 0.5^4 to 0.0625
36 × 1/x^4 × 0.0625x^4
Simplify
2.25x^4/x^4
Cancel x^4
<u>2.25</u>
3x + 4 = x+ 8 > 3x - x = 2x > 2x + 4 = 8 > 8 - 4 = 4 > 2x / 2 crosses out > 4 / 2 = 2 > x=2
2y + 5 = y + 7 > 2y - y = y > y+ 5 = 7 > 7-5= 2 > y=2
the perimeter of the kite is 4
<h3>I hope it is helpful for you .....</h3>
The point of intersection of the two lines is at (1,-1)
<h3>System of equation</h3>
The given system of expression is shown below
x - 2y = 3
5x + 3y = 2
The solution to the system of equation is the point of intersection
From equation 1
x = 3 + 2y
Substitute into 2
5(3+2y) + 3y = 2
15 +10y + 3y = 2
13y = -13
y = -1
Substitute y = -1 into 3
x = 3 + 2y
x = 3+(-2)
x = 1
Hence the point of intersection of the two lines is at (1,-1)
Learn more on system of equation here: brainly.com/question/25976025
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