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3 years ago

Represent in number line 1/5 and 2/5

Mathematics

2 answers:

vovangra [49]3 years ago

6 0

See picture for math work and answer.

sashaice [31]3 years ago

5 0

I’m not sure if I’m right but here’s my answer:

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Hi , step by step please

Zigmanuir [339]

Answer:

Eldest: $335,500 Middle: $182,750 Youngest: $167,750

Step-by-step explanation:

Let's represent the amount of money the youngest sibling received as x.

The amount the eldest received can be represented as: 2x

The amount the middle sibling received can be represented as: x + 15,000

If we combined the amount of money that all of the siblings received, it would be $686,000. We can write this as an equation:

686,000 = 2x + (x + 15,000) + x

Now let's solve for x. First, combine like terms

686,000 = 4x + 15,000

Subtract 15000 from both sides to isolate the 4x

671,000 = 4x

Divide both sides by 4 to isolate the x

167,750 = x

Now we know that the amount of money the youngest received is $167,750. We can use this amount to figure out how much the other two siblings received.

Eldest: 2 * 167,750 = $335,500

Middle: 167,750 + 15,000 = $182,750

We can check to make sure these answers are correct by adding them all together to make sure that they equal 686,000

167,750 + 335,500 + 182,750 = 686,000

7 0

3 years ago

Which number line correctly graphs the numbers in the list?

Oksana_A [137]

Answer:

the first option

Step-by-step explanation:

8 0

2 years ago

What is the y-intercept of (0,1) and (11,22)?

KATRIN_1 [288]

Answer:

the slope is 21/11 and the y-intercept is (0,1)

5 0

1 year ago

PLEASE ANSWER THIS QUESTION <br>Show that 4x – 7 is equivalent to 4(x - 1) – 3 when x = 3.

Drupady [299]

Answer:

4(3) - 7 = 4(3 - 1) - 3

12 - 7 = 4(2) - 3

5 = 8 - 3

= 5

They are equivalent because when they are both simplified they have the same answer 5

7 0

3 years ago

A metal beam was brought from the outside cold into a machine shop where the temperature was held at 65degreesF. After 5 min, t

ivolga24 [154]

Answer:

The beam initial temperature is 5 °F.

Step-by-step explanation:

If T(t) is the temperature of the beam after t minutes, then we know, by Newton’s Law of Cooling, that

$T(t)=T_a+(T_0-T_a)e^{-kt}$

where $T_a$ is the ambient temperature, $T_0$ is the initial temperature, $t$ is the time and $k$ is a constant yet to be determined.

The goal is to determine the initial temperature of the beam, which is to say $T_0$

We know that the ambient temperature is $T_a=65$ , so

$T(t)=65+(T_0-65)e^{-kt}$

We also know that when $t=5 \:min$ the temperature is $T(5)=35$ and when $t=10 \:min$ the temperature is $T(10)=50$ which gives:

$T(5)=65+(T_0-65)e^{k5}\\35=65+(T_0-65)e^{-k5}$

$T(10)=65+(T_0-65)e^{k10}\\50=65+(T_0-65)e^{-k10}$

Rearranging,

$35=65+(T_0-65)e^{-k5}\\35-65=(T_0-65)e^{-k5}\\-30=(T_0-65)e^{-k5}$

$50=65+(T_0-65)e^{-k10}\\50-65=(T_0-65)e^{-k10}\\-15=(T_0-65)e^{-k10}$

If we divide these two equations we get

$\frac{-30}{-15}=\frac{(T_0-65)e^{-k5}}{(T_0-65)e^{-k10}}$

$\frac{-30}{-15}=\frac{e^{-k5}}{e^{-k10}}\\2=e^{5k}\\\ln \left(2\right)=\ln \left(e^{5k}\right)\\\ln \left(2\right)=5k\ln \left(e\right)\\\ln \left(2\right)=5k\\k=\frac{\ln \left(2\right)}{5}$

Now, that we know the value of $k$ we can use it to find the initial temperature of the beam,

$35=65+(T_0-65)e^{-(\frac{\ln \left(2\right)}{5})5}\\\\65+\left(T_0-65\right)e^{-\left(\frac{\ln \left(2\right)}{5}\right)\cdot \:5}=35\\\\65+\frac{T_0-65}{e^{\ln \left(2\right)}}=35\\\\\frac{T_0-65}{e^{\ln \left(2\right)}}=-30\\\\\frac{\left(T_0-65\right)e^{\ln \left(2\right)}}{e^{\ln \left(2\right)}}=\left(-30\right)e^{\ln \left(2\right)}\\\\T_0=5$

so the beam started out at 5 °F.

6 0

3 years ago