Let y = 12 e^2x
e^2x = y/12
Taking
[email protected]ln e^2x = ln (y/12)
2x = ln (y/12)
x = (1/2) ln (y / 12)
so the inverse h-1(x) = (1/2) ln ( x / 12)
Here, AB ║ CD ; EF ⊥ AB
Number of 90 degree formed by the intersections of EF and two parallel lines AB and CD is 8
Hope this helps!
Answer:
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Step-by-step explanation:
mcm
Solution for 3n-2=15+3n equation:
Simplifying
3n + -2 = 15 + 3n
Reorder the terms:
-2 + 3n = 15 + 3n
Add '-3n' to each side of the equation.
-2 + 3n + -3n = 15 + 3n + -3n
Combine like terms: 3n + -3n = 0
-2 + 0 = 15 + 3n + -3n
-2 = 15 + 3n + -3n
Combine like terms: 3n + -3n = 0
-2 = 15 + 0
-2 = 15
Solving
-2 = 15
Couldn't find a variable to solve for.
This equation is invalid, the left and right sides are not equal, therefore there is no solution.
