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3 years ago

Helen draw a massive circle she the

Mathematics

1 answer:

alex41 [277]3 years ago

4 0

What do you mean what’s the question

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Write -72=2y^2-16y-20x in standard form

kifflom [539]

Answer:

-72=-12y-20x

Step-by-step explanation:

-72=2y^2-16y-20x

square the 2 keeping the variable

-72=4y-16y-20x

Then combine like terms in this case the numbers followed by y's

-72=-12y-20x

This is the standard form as there is nothing else you can combine to break this down any further

5 0

3 years ago

Read 2 more answers

Devisibility rules for 3, 6, and 9

fenix001 [56]

Answer:

★ Divisibility rule for 3 -

If the sum of all the digits divisible by 3 then the number is divisible by 3.

Here, we take an example for better understanding -

Example 1 - 3525

Add up the digits - 3 + 5 + 2 + 5

→ 15

As, 15 is divisible by 3. So, 3525 is a factor of 3.

★ Divisibility rule for 6 -

A number is to be divisible by 6 , if the number is also divisible by 2 and 3.

Example 2 - 132

Add up the digits = 1 + 3 + 2 = 6

As, 6 is divisible by 2 and it's also divisible by 3. Then, 132 is a factor of 6.

★ Divisibility rule for 9 -

If the sum of all the digits is divisible by 9 then the number is divisible by 9. Just like we'd in 3.

Example 3 - 1052

Add up the digits - 10 + 5 + 2 = 17

As, 17 is not divisible by 9. So, 1052 is also not divisible by 9.

3 0

3 years ago

HELPPPPPP PLEASEEEEE !!!!!

ollegr [7]

Answer:

m∠DBC is 43°

Step-by-step explanation:

Let us solve the question

∵ D is in the interior of ∠ABC

→ That means D divides ∠ABC into two angles ABD and DBC

∴ m∠ABD + m∠DBC = m∠ABC

∵ m∠ABD = (3x + 5)°

∵ m∠DBC = (5x - 7)°

∵ m∠ABC = 78°

→ Substitute them in the equation above

∴ 3x + 5 + 5x - 7 = 78

→ Add the like terms in the left side

∵ (3x + 5x) + (5 + -7) = 78

∴ 8x + -2 = 78

∴ 8x - 2 = 78

→ Add 2 to both sides

∴ 8x -2 + 2 = 78 + 2

∴ 8x = 80

→ Divide both sides by 8

∴ x = 10

→ To find m∠DBC, substitute x by 10 in its measure

∵ m∠DBC = 5(10) - 7

∴ m∠DBC = 50 - 7

∴ m∠DBC = 43°

3 0

3 years ago

Write an equation (a) in slope intercept form and (b) in standard form for the line passing through (1,9) and perpendicular to 3

maxonik [38]

Answer:

$\large\boxed{a)\ y=\dfrac{5}{3}x+\dfrac{22}{3}}\\\boxed{b)\ 5x-3y=-22}$

Step-by-step explanation:

$\text{The slope-intercept form of an equation of a line:}\\\\y=mx+b\\m-slope\\b-y-intercept\\\\\text{Let}\ k:y=m_1x+b_1,\ l:y=m_2x+b_2\\\\l\ \perp\ k\iff m_1m_2=-1\to m_2=-\dfrac{1}{m_1}\\\\l\ \parallel\ k\iff m_1=m_2\\\\=========================\\\\\text{We have the equation of a line in the standard form.}\\\text{Convert it to the slope-intercept form.}\\\\3x+5y=1\qquad\text{subtract}\ 3x\ \text{from both sides}\\\\5y=-3x+1\qquad\text{divide both sides bvy 5}\\\\y=-\dfrac{3}{5}x+\dfrac{1}{5}\to m_1=-\dfrac{3}{5}$

$a)\\\\y=m_2x+b\\\\m_1=-\dfrac{3}{5}\to m_2=-\dfrac{1}{-\frac{3}{5}}=\dfrac{5}{3}\\\\\text{Put the value of slope and the coordinates of the given point (1, 9)}\\\text{to the equation of a line:}\\\\9=\dfrac{5}{3}(1)+b\\\\9=\dfrac{5}{3}+b\qquad\text{subtract}\ \dfrac{5}{3}\ \text{from both sides}\\\\\dfrac{27}{3}-\dfrac{5}{3}=b\\\\\dfrac{22}{3}=b\\\\\text{Finally:}\\\\y=\dfrac{5}{3}x+\dfrac{22}{3}$

$b)\\\\\text{The standard form of an equation of a line:}\\\\Ax+By=C\\\\\text{Convert the equation}\ y=\dfrac{5}{3}x+\dfrac{22}{3}\ \text{to the standard form:}\\\\y=\dfrac{5}{3}x+\dfrac{22}{3}\qquad\text{multiply both sides by 3}\\\\3y=5x+22\qquad\text{subtract}\ 5x\ \text{from both sides}\\\\-5x+3y=22\qquad\text{change the signs}\\\\5x-3y=-22$

6 0

3 years ago

I will give 51 points to the person who answers this question

zavuch27 [327]

<h2>Solution :</h2>

= -5/8÷-3/4

After reciprocating =

= -5/8×4/-3

= 5/6

= -5/8×-3/4= 15/32

8 0

3 years ago