Answer:
multiple choice have 30 questions
word problems have 8 questions
Step-by-step explanation:
x=multiple choice. y=word problems
2x+5y=100 ---eq1
x+y=38 ---eq2
y=38-x ---eq3
substitutet eq3 into eq1
2x+5(38-x)=100
2x+(-5x)+190=100
2x-5x=100-190
-3x=-90
x=-90/-3
x=30
substitute x to eq3
y=38-(30)
y=8
multiple choice have 30 questions
word problems have 8 questions
Answer:
-8/7
Step-by-step explanation:
I thinks this is the answer
Conditional probablility P(A/B) = P(A and B) / P(B). Here, A is sum of two dice being greater than or equal to 9 and B is at least one of the dice showing 6. Number of ways two dice faces can sum up to 9 = (3, 6), (4, 5), (4, 6), (5, 4), (5, 5), (5, 6), (6, 3), (6, 4), (6, 5), (6, 6) = 10 ways. Number of ways that at least one of the dice must show 6 = (1, 6), (2, 6), (3, 6), (4, 6), (5, 6), (6, 6), (6, 5), (6, 4), (6, 3), (6, 2), (6, 1) = 11 ways. Number of ways of rolling a number greater than or equal to 9 and at least one of the dice showing 6 = (3, 6), (4, 6), (5, 6), (6, 3), (6, 4), (6, 5), (6, 6) = 7 ways. Probability of rolling a number greater than or equal to 9 given that at least one of the dice must show a 6 = 7 / 11
