Question

A cube is packed with decorative pebbles. If the cube has a side length of 2 inches, and each pebble weighs on average 0.5 lb per cubic inch, what is the total weight of the pebbles in the cube?

Answer 1

We can solve this problem by first solving for the total volume of the cube. The formula for volume of cube is given as:

V cube = s^3

Where s is the length of one side which is equivalent to 2 inches. Therefore:

V cube = (2 inches)^3

V cube = 8 cubic inch

 

Assuming that all the pebble fills the cube without any spaces, then the total weight of the pebbles in the cube would simply be:

Total weight = 0.5 lb per cubic inch * 8 cubic inch

Total weight = 4 lb

 

Therefore, the total weight of the pebbles in the cube is 4 lbs.