A cube is packed with decorative pebbles. If the cube has a side length of 2 inches, and each pebble weighs on average 0.5 lb pe r cubic inch, what is the total weight of the pebbles in the cube?
1 answer:
We can solve this problem by first solving for the total
volume of the cube. The formula for volume of cube is given as:
V cube = s^3
Where s is the length of one side which is equivalent to
2 inches. Therefore:
V cube = (2 inches)^3
V cube = 8 cubic inch
Assuming that all the pebble fills the cube without any
spaces, then the total weight of the pebbles in the cube would simply be:
Total weight = 0.5 lb per cubic inch * 8 cubic inch
Total weight = 4 lb
Therefore, the total weight of the pebbles in the cube is <u>4
lbs</u> .
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Answer:
x = 95
Step-by-step explanation:
(2x - 60)° = (x + 35)° (corresponding angles are congruent)
2x - 60 = x + 35
2x - 60 - x = x + 35 - x
x - 60 = 35
x - 60 + 60 = 35 + 60
x = 95
A "regular quadrilateral" is a square, so the length and width are both 4 cm. The surface area of a rectangular prism is given by
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