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The y-coordinate of the midpoint, M of the segment AB described by; A(-3,3) and B(5,7) is; 5.
<h3>What is the y-coordinate of the point M which is the midpoint of AB, defined by;
A(-3,3) and
B(5,7).</h3>
It follows from the task content that the y-coordinate of the midpoint, M of AB defined by; A(-3,3) and B(5,7) is to be determined.
Hence, it follows from coordinate geometry that the y-coordinate of the midpoint is such that;
y = (y(1) +y(2))/2
y = (3 + 7)/2
y = 5.
Ultimately, the y-coordinate of the midpoint of AB; A(-3,3) and B(5,7) is; y =5.
Read more on midpoint of a line;
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From the given function modeling the height of the ball:
f(x)=-0.2x^2+1.4x+7
A] The maximum height of the ball will be given by:
At max height f'(x)=0
from f(x),
f'(x)=-0.4x+1.4
solving for x we get:
-0.4x=-1.4
x=3.5ft
thus the maximum height would be:
f(3.5)=-0.2(3.5)^2+1.4(3.5)+7
f(3.5)=9.45 ft
b]
How far from where the ball was thrown did this occur:
from (a), we see that at maximum height f'(x)=0
f'(x)=-0.4x+1.4
solving for x we get:
-0.4x=-1.4
x=3.5ft
This implies that it occurred 3.5 ft from where the ball was thrown.
c] How far does the ball travel horizontally?
f(x)=-0.2x^2+1.4x+7
evaluationg the expression when f(x)=0 we get:
0=-0.2x^2+1.4x+7
Using quadratic equation formula:
x=-3.37386 or x=10.3739
We leave out the negative and take the positive answer. Hence the answer 10.3739 ft horizontally.
15 and the error is on step 3
Reasoning:
I’m not certain how they got 1.5 but you basically divide both sides by two, the 2 would be canceled and you would be left with w, divide 30 by 2 and you get w=15, sorry i suck at explaining
Answer:
19/20
Step-by-step explanation:
