The circle below is centered at the point (1, 2) and has a radius of length 2. What is its equation?

2 answers:

7 0

$The\ equation\ of\ the\ circle:(x-a)^2+(y-b)^2=r^2\\\\(a;\ b)-the\ center;\ r-the\ radius\\-------------------------\\\\(1;\ 2)\to a=1\ and\ b=2;\ r=2\\\\subtitute:\\\\(x-1)^2+(y-2)^2=2^2\\\\\boxed{(x-1)^2+(y-2)^2=4}$

statuscvo [17]3 years ago

5 0

Quite frankly, I don't see any circle below.

But the equation of the circle that you've described is . . .

<em>(x - 1)² + (y - 2)² = 4</em> .

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