The circle below is centered at the point (1, 2) and has a radius of length 2. What is its equation?

2 answers:

7 0

$The\ equation\ of\ the\ circle:(x-a)^2+(y-b)^2=r^2\\\\(a;\ b)-the\ center;\ r-the\ radius\\-------------------------\\\\(1;\ 2)\to a=1\ and\ b=2;\ r=2\\\\subtitute:\\\\(x-1)^2+(y-2)^2=2^2\\\\\boxed{(x-1)^2+(y-2)^2=4}$

statuscvo [17]3 years ago

5 0

Quite frankly, I don't see any circle below.

But the equation of the circle that you've described is . . .

(x - 1)² + (y - 2)² = 4 .

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To make concrete it take 8 parts crushed gravel, 7 parts water and 5 parts cement mix. A worker needs to make 220 kg of concrete

Romashka-Z-Leto [24]

A complete load of concrete = 8 parts gravel + 7 parts water + 5 parts cement.

Total number of parts in every load = 8 + 7 + 5 = 20 parts

If total load = 220 kg, then 20 parts = 220 kg

Divide each side by 20 : 1 part = 11 kg

gravel = 8 parts = 8 x 11 kg = 88 kg
water = 7 parts = 7 x 11 kg = 77 kg
cement = 5 parts = 5 x 11 kg = 55 kg

Check: 88 + 77 + 55 = 220 yay !

4 0

3 years ago

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