Answer: No solutions
Step-by-step explanation:
There are no solutions to 0 = x² - x + 1.
[Method One]
We can solve this by rewriting the equation, but it is quicker to graph it when there are no solutions. See attached.
[Method Two]
I said we can solve this by solving an equation, here it is. We will use the quadratic formula since the equation given is already in the proper form.
-> Negative numbers don't have real square roots, so there is no solution
Answer: Choice D) 11
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Work Shown:
cos(angle) = adjacent/hypotenuse
cos(35) = 9/x
x*cos(35) = 9
x = 9/cos(35)
x = 10.9869712988531 ... make sure your calculator is in degree mode
x = 11 ... rounding to the nearest tenth
<span>To solve the problem, to 40%
of the total customer should be solve. And this can be solve by muliplting it
by the fraction (0.4). so 140 x 0.4 = 56 customers. Since Trudy has already 60
of her sutomers job ready then she met her target.</span>
The critical points are at x = 1 and x = 4 giving you the intervals (-inf, 1), (1, 4) and (4, inf).
By substituting x values in these 3 intervals, you can see that f'(x) is positive in the first and third intervals and negative in the second interval.
This means that f(x) is increasing in the first and third intervals and decreasing in the second interval.
The answer is D.
Considering the given stem-and-leaf plot, the quartiles are given as follows:
- The first quartile is of 67.5.
- The second quartile, which is the median, is of 84.5.
- The third quartile is of 91.5.
<h3>What are the median and the quartiles of a data-set?</h3>
- The median of the data-set separates the bottom half from the upper half, that is, it is the 50th percentile.
- The first quartile is the median of the first half of the data-set.
- The third quartile is the median of the second half of the data-set.
There is an even number of elements(26), hence the median is the mean of the 13th and 14th elements, which are 83 and 86, hence:
Me = (83 + 86)/2 = 84.5.
The first half has 12 elements, hence the first quartile is the mean of the 6th and 7th elements, which are 67 and 68, hence:
Q1 = (67 + 68)/2 = 67.5.
The third half also has 12 elements, starting at the second 86, hence the third quartile is the mean of the 6th and 7th elements of this half, hence:
Q3 = (91 + 92)/2 = 91.5.
More can be learned about the quartiles of a data-set at brainly.com/question/28017610
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