Answer:
The population will reach 34,200 in February of 2146.
Step-by-step explanation:
Population in t years after 2012 is given by:

In what month and year will the population reach 34,200?
We have to find t for which P(t) = 34200. So



Solving a quadratic equation:
Given a second order polynomial expressed by the following equation:
.
This polynomial has roots
such that
, given by the following formulas:



In this question:

So 
Then



We only take the positive value.
134 years after 2012.
.14 of an year is 0.14*365 = 51.1. The 51st day of a year happens in February.
So the population will reach 34,200 in February of 2146.
Answer:
I believe the answer you are looking for is C-√57
Mark brainliest :)
<span>7e^(×/3)=14
</span><span>e^(×/3)=14/7
</span>e^(×/3)=2
take ln of both sides;
lne^(×/3)=ln2
****You should be familiar that lne^x=x as ln is the inverse function of e and vice versa****
then;
x/3=ln2
x=3ln2
x approximately is equal to 2.1
Let the required point be (a,b)
The distance of (a,b) from (7,-2) is
= 
But this distance needs to be betweem 50 & 60
So

Squaring all sides
2500 < (a-7)² + (b+2)² < 3600
Let a = 7
So we have
2500 < (b+2)² <3600
b+2 < 60 or b+2 > -60 => b <58 or b > -62
Also
b+2 >50 or b + 2 < -50 => b >48 or B < -52
Let us take one value of b < 58 say b = 50
So now we have the point as (7, 50)
The other point is (7,-2)
Distance between them
= 
This is between 50 & 60
Hence one point which has a distance between 50 & 60 from the point (7,-2) is (7, 50)