The end of a hose was resting on the ground, pointing up an angle. Sal measured the path of the water coming out of the hose and
found that it could be modeled using the equation f(x) = –0.3x2 + 2x, where f(x) is the height of the path of the water above the ground, in feet, and x is the horizontal distance of the path of the water from the end of the hose, in feet.
When the water was 4 feet from the end of the hose, what was its height above the ground?
A. 3.2 feet
B. 4.8 feet
C. 5.6 feet
D. 6.8 feet
When the water was 4 feet from the end of the hose, what was its height above the ground?
A. 3.2 feet
B. 4.8 feet
C. 5.6 feet
D. 6.8 feet
2 answers:
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Answer:
d=10u
Q(5/3,5/3,-19/3)
Step-by-step explanation:
The shortest distance between the plane and Po is also the distance between Po and Q. To find that distance and the point Q you need the perpendicular line x to the plane that intersects Po, this line will have the direction of the normal of the plane , then r will have the next parametric equations:
To find Q, the intersection between r and the plane T, substitute the parametric equations of r in T
Substitute the value of in the parametric equations:
Those values are the coordinates of Q
Q(5/3,5/3,-19/3)
The distance from Po to the plane