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liraira [26]
4 years ago
13

Please hurry. showw all work

Mathematics
1 answer:
kvasek [131]4 years ago
7 0

Can you give me an example of how your teacher wants it done?

ill help you as much as i can to give you a A!

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Rita received a $90 gift card for a coffee store. She used it in buying some coffee that cost $8.07 per pound. After buying the
laila [671]
Subtract 41.58 by 9 then devide that number by 8.07 to get the amount of pounds purchased your answer is 6
7 0
4 years ago
Need help please.........................
Archy [21]

Answer:

16t^{2} + 2t - 6

Step-by-step explanation:

(12t^{2}  + 5t -y) - (-4t^{2} + 3t -1)

simplify

12t^{2} + 5t -7 +4t^{2} -3t +1

combine like terms

16t^{2} + 2t - 6

8 0
3 years ago
286 children enter the brass band competition.There are 27 teachers who accompany them and 19 parents.How many people visit the
shutvik [7]

Answer:

332

Step-by-step explanation:

286+27+19

8 0
4 years ago
Read 2 more answers
Perform the following computations.You may use13≈0.333333,34= 0.75 and100301= 0.332226.(i). Compute13+34by using five significan
White raven [17]

Answer:

a. 1.0833

Absolute Error = 0.416667

Relative Error = 1.250002

b. 0.0011070

Absolute Error = 0.0011070

Relative Error = 0.003321

Step-by-step explanation:

Given

1/3 = 0.333333

3/4 = 0.75

100/301 = 0.332226

a.

1/3 + 3/4

= 0.333333 + 0.75

= 1.083333

= 1.0833 ------ Approximated to 5 significant digits

Absolute Error = |Real Value - Estimated Value|

Relative Error = Absolute Error/Real Value

Assume 1/3 to be the real value and 3/4 to be the estimated value

Absolute Error = |0.333333 - 0.75|

Absolute Error = |-0.416667|

Absolute Error = 0.416667

Relative Error = 0.416667/0.333333

Relative Error = 1.250002

b.

1/3 - 100/301

= 0.333333 - 0.332226

= 0.001107

= 0.0011070 ----- Approximated to 5 significant digits

Assume 1/3 to be real value and 100/301 to be estimated value

Absolute Error = 0.333333 - 0.332226

Absolute Error = 0.0011070

Relative Error = 0.0011070/0.333333

Relative Error = 0.003321

Absolute and relative errors are approximation errors and they are due to the discrepancy between an exact value and some approximation to them.

The absolute error is the magnitude of the difference between the exact value and the approximation. The relative error is the absolute error divided by the magnitude of the exact value

4 0
4 years ago
Which function BEST expresses the linear relationship displayed by the scatter plot?
Harrizon [31]

Answer:

C

Step-by-step explanation:

We want a line of best fit, which means we want to create a line that the data points will lie closest to.

One thing we can do is find the slope between the bottom-leftmost point and the top-rightmost point. This is because if we were to draw a line connecting these two, it will cut through the data quite well.

Those two points are (9, 15) and (16, 18), so the slope is change in y divided by the change in x:

(18 - 15) ÷ (16 - 9) = 3 ÷ 7 ≈ 0.4

Eliminate A and B.

Now we need to determine the y-intercept. This needs no calculations; simply look at the graph: there's no way a line cutting through the y-intercept point of (0, 18) will perfectly match the data points; instead it must be a y-intercept lower than 18. So, eliminate D.

The answer is C.

6 0
3 years ago
Read 2 more answers
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