Could just be used as a variable.
The first thing I'll do is solve "5y = 2x + 20" for "<span>y=</span>", so that I can find my reference slope:
y = (2/5)x + 4;
So the reference slope from the reference line is <span>m = 2/5;</span>.
Now I need to find two new slopes, and use them with the point they've given me; namely, with the point (-1, 3). They want me to find the line through (4, –1) that is parallel to 5y = 2x + 20; that is, through the given point, they want me to find a line that has the same slope as the reference line.
Since a parallel line has an identical slope, then the parallel line through (-1, 3) will have slope <span>m = 2/5</span>. Now I have a point and a slope! So I'll use the point-slope form to find the line: y - 3 = (2/5)( x + 1);
Finally, y = (2/5)x + 17/5;
Answer:
34 years
Step-by-step explanation:
f = s + 28 Eq. 1
f+8 = 3(s+8) Eq. 2
f = father age
s = son age
replacing Eq. 1 on Eq. 2
(s+28) + 8 = 3(s+8)
s + 36 = 3*s + 3*8
s + 36 = 3s + 24
36 - 24 = 3s - s
12 = 2s
12/2 = s
s = 6
from the Eq. 1
f = 6 + 28
f = 34
Check
from the Eq. 2
34+8 = 3(6+8)
42 = 3*14
Answer:
a - Right angled triangle
b - Parallelogram
c - Square
d - kite
Step-by-step explanation:
Hope this helps
Goodluck
Answer: Ox²1
Ox≤23
2 3
4
5 6
X
Step-by-step explanation:
Ox²1
Ox≤2
4
Oy²-3
2 3
4
5 6
X
hehehehehehehehehehhehehehehehehe
