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4 years ago

18x^2+21x-9 I need to figure out how to work this problem

2 answers:

3 0

$18x^2+21x-9=3(6x^2)+3(7x)-3(3)\\\\=3(6x^2+7x-3)=3(6x^2+9x-2x-3)\\\\=3[3x(2x)+3x(3)-1(2x)-1(3)]\\\\=3[3x(2x+3)-1(2x+3)]\\\\=\boxed{3(2x+3)(3x-1)}$

Goshia [24]4 years ago

3 0

18x^2 + 21x - 9. Factor out a 3.

3(6x^2 + 7x - 3). Factor the trinomial. 

3(3x - 1)(2x + 3). Answer

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Two identical triangles form a parallelogram with a base of 8 Inches and a height of 6 inches.What is the area of one triangle?

dedylja [7]

Answer: The area of the triangle is 24 square inches

Step-by-step explanation:

Hi, since the 2 triangles form a parallelogram ( see attachment) we have the base and height of the triangles, we have to apply the next formula:

Area of a triangle; (base x height) /2

Replacing with the values:

A = (8x6 )/2

A = 48 /2

A = 24 square inches

The area of the triangle is 24 inches

Feel free to ask for more if needed or if you did not understand something.

4 0

3 years ago

Someone help me asap/math 10

zysi [14]

Answer:

Step-by-step explanation:

Y is the hypotenuse. It is side opposite to the right angle.

Zis the length opposite theta. It is the side right opposite to the sign.

X is the side adjacent to theta. It is the one that is in contact with that angle apart from the hypotenuse.

Hope this helps

4 0

4 years ago

Read 2 more answers

I WILL MARK BRAINLIST

ANEK [815]

Answer:

corresponding angle are all congruent

7 0

3 years ago

5 times a number is less than 2 times that same number minus 9, what must be the value of the number?

zzz [600]

EQUATION: 5x = 2x - 9
Add 9 to both sides
NEW EQUATION: 5x + 9 = 2x
Subtact 5x from both sides:
NEW EQUATION: 9 = -3x
Divide -x on bith sides
NEW EQUATION: -3 = x, or x=-3

5 0

4 years ago

For a data set with a mean of 150 and a standard Deviation of 15, use chebyshev theorem to find the interval of which 75% of the

svp [43]

The Chebychev's theorem states that for any numerical data set,
1.) at least $\frac{3}{4}$ of the data lie within two standard deviations of the mean;
2.) at least $\frac{8}{9}$ of the data lie within three standard deviations of the mean;
3.) at least $1-\frac{1}{k^2}$ of the data lie within k standard deviations of the mean, where k is any positive whole number that is greater than 1.

Thus, given a data set with a mean of 150 and a standard Deviation of 15, 75% of the data represent $\frac{3}{4}$ of the data, and according to Chebychev's theorem, at least $\frac{3}{4}$ of the data lie within two standard deviations of the mean.

Thus, 75% of the data will fall within the interval
$150\pm2(15)=150\pm30=(150-30,\ 150+30)=(120,\ 180)$ .

Therefore, 75% of the data will fall within the interval 120 to 180.

7 0

3 years ago