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Black_prince [1.1K]
3 years ago
15

18x^2+21x-9 I need to figure out how to work this problem

Mathematics
2 answers:
shtirl [24]3 years ago
3 0
18x^2+21x-9=3(6x^2)+3(7x)-3(3)\\\\=3(6x^2+7x-3)=3(6x^2+9x-2x-3)\\\\=3[3x(2x)+3x(3)-1(2x)-1(3)]\\\\=3[3x(2x+3)-1(2x+3)]\\\\=\boxed{3(2x+3)(3x-1)}
Goshia [24]3 years ago
3 0
18x^2 + 21x - 9. Factor out a 3. 

<span>3(6x^2 + 7x - 3). Factor the trinomial. </span>

<span>3(3x - 1)(2x + 3). Answer </span>
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_____________________________________

\sf\huge\underline\red{SOLUTION:}

Use formula:

\sf{V = \pi(\frac{d}{2})^2h}

Solving for diameter:

\sf d = 2 \times  \sqrt{ \frac{V}{\pi h} }  \\ \sf = 2 \times   \sqrt{ \frac{40}{\pi \times 1800} } \approx0.16821 \\  = \sf \large\boxed{\sf{\green{d = 0.17}}}

\sf\huge\underline\red{FINAL \: ANSWER}

\large\boxed{\sf{\green{d=0.17}}}

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