PLS HELP WILL GIVE BRANLIEST

Need answers nowww

rusak2 [61]

Answer:

i thinks its a. integers

Step-by-step explanation:

hope its help and soory if im wrong

6 0

2 years ago

a photographer shines a camera light at a particular painting forming an angle of 50 degrees with a camera platform at the light

umka2103 [35]

Answer:

The painting is 42.13 feet above the platform

Step-by-step explanation:

Refer the attached figure .

A particular painting forming an angle of 50 degrees with a camera platform .

∠ABC = 50°

We are also given that the light is 55 feet from the wall where the painting hangs

i.e. AB = 55 feet.

Now we are required to find how high above the platform is the painting. i.e. AC

So, we will use trigonometric ratio :

$sin\theta = \frac{Perpendicular}{Hypotenuse}$

$sin50^{circ} = \frac{AC}{AB}$

$sin50^{circ} = \frac{AC}{55}$

$0.766*55 = AC$

$42.13= AC$

Thus the painting is 42.13 feet above the platform

8 0

3 years ago

If diameter of a circle is twice as large as the diameter of a smaller circle, What

Leona [35]

The area of a circle uses the radius of a circle, which is 1/2 the diameter.

In the calculation the radius is squared.

Since the diameter of the larger circle is twice as large the radius would be 2 times.

2 squared would be: 2^2 = 4

This means the area of the larger circle is 4 times larger which would make the ratio 4:1

3 0

2 years ago

Please help this is due in 20 mins, I will give brainliest

eduard

Answer:

L = 5 $\sqrt{10}$

Step-by-step explanation:

use Pythagorean Theorem:

L² + (5 $\sqrt{2}$ )² = (10 $\sqrt{3}$ )²

L² + 25(2) = 100(3)

L² + 50 = 300

L² = 250

L = $\sqrt{250}$ = $\sqrt{25}$ · $\sqrt{10}$ = 5 $\sqrt{10}$

6 0

2 years ago

Read 2 more answers

In a survey of 603 adults, 98 said that they regularly lie to people conducting surveys. Create a 99% confidence interval for th

marysya [2.9K]

Answer:

The population proportion is estimated to be with 99% confidence within the interval (0.1238, 0.2012).

Step-by-step explanation:

The formula for estimating the population proportion by a confidence interval is given by:

$\hat{p}\pm z_{\alpha /2}\times\sqrt{\frac{\hat{p}\times(1-\hat{p})}{n}}$

Where:

$\hat{p}$ is the sample's proportion of success, which in this case is the people that regularly lie during surveys,

$z_{\alpha /2}$ is the critical value needed to find the tails of distribution related to the confidence level,

$n$ is the sample's size.

<u>First</u> we compute the $\hat{p}$ value:

$\hat{p}=\frac{successes}{n}=\frac{98}{603}=0.1625$

<u>Next</u> we find the z-score at any z-distribution table or app (in this case i've used StatKey):

$z_{\alpha /2}=2.576$

Now we can replace in the formula with the obtained values to compute the confidence interval:

$\hat{p}\pm z_{\alpha /2}\times\sqrt{\frac{\hat{p}\times(1-\hat{p})}{n}}=0.1625\pm 2.576\times\sqrt{\frac{0.1625\times(1-0.1625)}{603}}=(0.1238, 0.2012)$

5 0

2 years ago