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AURORKA [14]
4 years ago
11

A cylinder and a cone have the same diameter:8 inches. The height of the cylinder is 3 inches.The height of the cone is 18 inche

s. What is the relationship between the volume of this cylinder and this cone?
Mathematics
1 answer:
sesenic [268]4 years ago
3 0

The volume of cone is double of the volume of cylinder.

Further explanation:

We have to find both volumes first to compare the volumes of both.

Volume of Cylinder:

Given

Diameter = d = 8 inches

Radius=r=\frac{d}{2}=\frac{8}{2}=4\ inches

Height of cylinder=h=3 inches

V_{Cyl}=\pi r^2h\\=3.14*(4)^2*3\\=3.14*16*3\\=150.72\ in^3

Volume of Cone:

Radius=r=4 inches

Height of cone= h= 18 inches

V_{con}=\frac{1}{3}\pi r^2h\\=\frac{1}{3}*3.14*(4)^2*18\\=\frac{1}{3}*3.14*16*18\\=301.44\ in^3

We can see that

2V_{cyl}=V_{Con}

The volume of cone is double of the volume of cylinder.

Keywords: Volume, Volume of cone

Learn more about volume at:

  • brainly.com/question/4390083
  • brainly.com/question/4401748

#learnwithBrainly

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Answer:

The answer is

<h2>\sqrt{29}  \:  \:  \: or \:  \:  \:5.38 \:  \:  \: units</h2>

Step-by-step explanation:

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d =  \sqrt{ ({x1 - x2})^{2} +  ({y1 - y2})^{2}  }  \\

where

(x1 , y1) and (x2 , y2) are the points

From the question the points are

A(1,3) and B(6,5)

The length is

|AB|  =  \sqrt{ ({1 - 6})^{2} +  ({3 - 5})^{2}  }  \\  =  \sqrt{ ({ - 5})^{2}  + ( { - 2})^{2} }  \\  =  \sqrt{25 + 4}  \\  =  \sqrt{29}

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