15) In the year that $50.00 Canadian bought
1 answer:
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sin2x+sinx-2cox-1=0
As we know, Sin 2x =2sinx cosx
2Sinx Cosx+Sinx-2cosx-1=0
Sinx(2cos x+1)-1(2cosx+1)=0
(sinx-1)(2cosx+1)=0
So, either sinx-1=0 or 2cos x+1=0
Sin x=1 or cos x=
x= or multiples of
x= or multiples of
x= or multiples of
