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HACTEHA [7]
3 years ago
8

On a true-false quiz of six questions, Karen answers all the questions. What is the probability that she answers the first three

questions correctly and the last three questions incorrectly?
Mathematics
2 answers:
erastovalidia [21]3 years ago
8 0

Answer: The probability of three correct answers and three incorrect answers is \frac{1}{64}

Step-by-step explanation:

Since we have given that

There is a true - false quiz of six questions.

Probability of getting a true = \frac{1}{2}

Probability of getting a false = \frac{1}{2}

Probability that she answers the first three questions correctly and the last three questions incorrectly is given by

P(Three correct) × P(Three incorrect)

(\frac{1}{2}\times \frac{1}{2}\times \frac{1}{2})\times (\frac{1}{2}\times \frac{1}{2}\times \frac{1}{2})\\\\=(\frac{1}{2})^6\\\\=\frac{1}{64}

Hence, the probability of three correct answers and three incorrect answers is \frac{1}{64}

Alisiya [41]3 years ago
6 0

Answer:

<h2>1/64</h2>

Step-by-step explanation:

just took the test and got 100% :)



Have a nice day!!

- <em> Shadow</em>


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Read 2 more answers
A positive integer is twice another.the sum of the reciprocal of the two positive integer is 3/14. Find the integers
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Answer:

\huge\boxed{14\ \text{and}\ 7}

Step-by-step explanation:

n,\ m-\text{positive integer}\\\\n=2m-\text{a positive integer is twice another}\\\\\dfrac{1}{n}+\dfrac{1}{m}=\dfrac{3}{14}-\text{the sum of the reciprocal of the two positive integer is }\ \dfrac{3}{14}\\\\\text{We have the system of equations:}\\\\\left\{\begin{array}{ccc}n=2m&(1)\\\dfrac{1}{n}+\dfrac{1}{m}=\dfrac{3}{14}&(2)\end{array}\right

\text{Substitute (1) to (2):}\\\\\dfrac{1}{2m}+\dfrac{1}{m}=\dfrac{3}{14}\\\\\dfrac{1}{2m}+\dfrac{1\cdot2}{m\cdot2}=\dfrac{3}{14}\\\\\dfrac{1}{2m}+\dfrac{2}{2m}=\dfrac{3}{14}\\\\\dfrac{1+2}{2m}=\dfrac{3}{14}\\\\\dfrac{3}{2m}=\dfrac{3}{14}\Rightarrow2m=14\qquad\text{divide both sides by 2}\\\\\dfrac{2m}{2}=\dfrac{14}{2}\\\\\boxed{m=7}

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Jasmin, Quinn, and Maddy are rock climbing. Jasmin is 42 ½ feet below Quinn. Maddy is 67 ¾ feet above Jasmin. What is Maddy's po
ladessa [460]

Answer:

25\frac{1}{4} feet

<em />

Step-by-step explanation:

Given

Maddy = 67\frac{3}{4} above Jasmin

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Required

Determine Maddy's position relative to Quinn's

From the given parameter, one can easily deduce that Quinn is in between Maddy and Jasmin (See attachment)

Using the attachment as a point of reference;

z = 67\frac{3}{4}

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Convert to improper fractions

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